Explicitly numbered string?

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nilsotto
nilsotto am 28 Feb. 2016
Kommentiert: nilsotto am 28 Feb. 2016
Hi,
How do I explicitly define a string with numbering? Look at the example below. Suppose "numbers" are unknown and I want to name the figures Q1, Q2 etc.
numbers=3;
fname={'Q1' 'Q2' 'Q3'};
for i=1:numbers
if i==1
x = -2*pi:0.01:2*pi;
elseif i==2
x = -3*pi:0.01:3*pi;
else
x = -4*pi:0.01:4*pi;
end
y = sin(x);
h=figure
plot(x,y);
print(h,'-dpng',fname{1,i});
end

Antworten (2)

Guillaume
Guillaume am 28 Feb. 2016
My recommendation is to use sprintf which lets you compose any arbitrary string that you want.
fnames = cell(1, numbers);
for i = 1:numbers
fname{i} = sprintf('Q%d', i);
end
Or as a one-liner:
fnames = cellfun(@(n) sprintf('Q%d', n), 1:numbers, 'UniformOutput', false);
Note that the format string of sprintf is very flexible. If you had more than 10 numbers and wanted to generate: Q01, Q02, ..., Q10, etc.:
sprintf('Q%02d', i)
  2 Kommentare
Jan
Jan am 28 Feb. 2016
Unfortunately undocumented yet:
fnames = sprintfc('Q%d', 1:numbers)
nilsotto
nilsotto am 28 Feb. 2016
Many thanks guys!

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Azzi Abdelmalek
Azzi Abdelmalek am 28 Feb. 2016
numbers=3;
fname=genvarname(repmat({'Q'},1,numbers),'Q')
for ii=1:numbers
x = -(ii+1)*pi:0.01:(ii+1)*pi;
y = sin(x);
h=figure
plot(x,y);
print(h,'-dpng',fname{ii});
end
  1 Kommentar
Guillaume
Guillaume am 28 Feb. 2016
While genvarname would work in this case, it's not for generating abritrary strings, only valid variable names. The set of valid filenames is much greater than the set of valid variable names.

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