for loop for the function
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Hi all, here is my function
function [error] =stress5_function(Ke,n,Sult,u,t,S0,k,m)
pa=0.1013 ;
S3=5 ;
Ei=Ke.*pa.*(S3./pa).^n;
Rf=(S0+k.*exp(-(S3./m)))./(Sult+u.*exp(-(S3./t)));
% z=(£m1-£m3)
z=0:0.0001:5;
Et=Ei.*(1-(Rf.*z)./(S0+k.*exp(-(S3./m))));
Et(Et<0)=0;
x=(z./Et).*100;
A=xlsread('5MPa','A1:A32');
B=A';
C=xlsread('5MPa','B1:B32');
D=C';
startingIndex = find(x==0);
endingIndex = find(x>=16);
desiredX = x(startingIndex:endingIndex);
desiredZ = z(startingIndex:endingIndex);
A1 = trapz(desiredX,desiredZ);
A2= trapz(B,D);
error= ((A1-A2)./A1)*100;
end
there are 8 parameters in the function and the value of the parameters, I stored in an excel file
Ke=xlsread('parameters','A2:A9096');
n=xlsread('parameters','B2:B9096');
Sult=xlsread('parameters','C2:C9096');
u=xlsread('parameters','D2:D9096');
t=xlsread('parameters','E2:E9096');
S0=xlsread('parameters','F2:F9096');
k=xlsread('parameters','G2:G9096');
m=xlsread('parameters','H2:H9096');
pa=0.1013 ;
S3=5 ;
I want to create a for loop to run the function what should I write??
1 Kommentar
Antworten (1)
Your funtion accepts vectors as input. So there is no need to call it through a for loop. But if you really want to do this:
err = zeros(size(Ke));
for i = 1:numel(Ke)
err(i) = stress5_function(Ke(i),n(i),Sult(i),u(i),t(i),S0(i),k(i),m(i));
end
Better read the 5MPa file once only and provide the contents as inputs:
B = xlsread('5MPa','A1:A32').';
D = xlsread('5MPa','B1:B32').';
2 Kommentare
Coleman
am 25 Feb. 2016
Use the debugger to step throught your code line by line, until you find the reason for the unexpected values. Please note, that we cannot do this for you, because we do not have the input data and cannot guess, why you assume a vlue different from Inf.
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