I have a training label for 3 different classes in a matrix of size 1*178 example t=[1 1 1 3 1 2 3 1 ... .....]. Anyone please help me to write an efficient code for generating a new matrix of size 3*178 where based on the value in "t", the corresponding location in columns should be 1.
for the above example. the output will be like the following matrix:
[1 1 1 0 1 0 0 1.... 0 0 0 0 0 1 0 0..... 0 0 0 1 0 0 1 0.....]

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Stephen23
Stephen23 am 24 Feb. 2016
Bearbeitet: Stephen23 am 24 Feb. 2016

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For a simple generalized solution use bsxfun:
>> t = [1 1 1 3 1 2 3 1]
>> bsxfun(@eq,(1:3).',t)
ans =
1 1 1 0 1 0 0 1
0 0 0 0 0 1 0 0
0 0 0 1 0 0 1 0

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Jab
am 24 Feb. 2016

Bearbeitet:

am 24 Feb. 2016

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