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Accessing empty array element through a loop

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Harsha
Harsha am 21 Feb. 2016
Kommentiert: Harsha am 28 Feb. 2016
I have following program
r = 0;
syms x y z
Base = x*y*z;
for j = 1:8
r = r+1;
X(r) = j;
x = X(r);
AN = eval(Base);
Base1(r) = AN;
end
First_Int = (Base1(1,1)+ 4*Base1(1,2)+ 2*Base1(1,3) + 4*Base1(1,4)+ 2*Base1(1,5)+ 4*Base1(1,6)+ 2*Base1(1,7)+ 4*Base1(1,8)+Base1(1,9))/(3);
It is clear that array size is increasing dynamically and consume much time. There will be two other loops for y and z to complete the calculation with values.
Can I have an alternative way of doing this to save time and memory?

Antworten (1)

Geoff Hayes
Geoff Hayes am 21 Feb. 2016
Harsha - I'm not clear on how your question title accessing empty array element relates to your code. Where are you trying to access an empty element?
If you are concerned with the array size increasing dynamically on each iteration of the loop, then pre-allocate or size the array before entering the loop as
n = 8;
X = zeros(n,1);
Base1 = zeros(n,1);
for k=1:n
X(k) = k;
Base1(k) = k*y*z;
end
It may be that you need to show your outer loops where y and z are initialized. Note how in the above, I have removed the need for the indexing variable r as k can do the same. I use k as MATLAB uses i and j to represent the imaginary number.
  5 Kommentare
Geoff Hayes
Geoff Hayes am 23 Feb. 2016
Bearbeitet: Geoff Hayes am 23 Feb. 2016
Harsha - what is Base1 supposed to be? An array of symbols or scalar values? I don't understand why your are using symbols for xi, xj, yi, yj, zi and zj.
Harsha
Harsha am 28 Feb. 2016
This is a procedure to perform numerical integration using Simpson's rule. Base1 is defined in the loop, which consists of evaluated values of Base_function with respect to xi variable. Just consider this as a integration whose values of variables will be evaluated at each step.

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