How to apply at each cell a division

Hi, I've a 1500x1500 double cells, I want to apply a division for a number took it from a 4000x1 double cells, and do it in a for cycle.

I wrote a code that open my files from a directory, but I know that I have to use cellfun comand to do that.

Thanks in advance

Stefano

[Jan]

I do not unserstand the question. Do you have a {1500 x 1500} cell array containing scalar doubles, or a {1 x 1} cell containing a [1500 x 1500] double matrix? How do you want to obtain 400x1 "double cells" and again: what is a "double cell"?

You do not have to use cellfun, because a loop is sufficient also.

[Stefano Alberti]

Thank you, Jan. I have a matrix 1500x1500 (double format), inside a for cycle that have to divide for a values stored inside a matrix 4000x1, each cycle has to use values from 4000x1 positionated in 1x1 2x1 3x1 ecc ecc

[dpb]

This is still extremely difficult to understand the intent, given the language barrier. Showing a small actual data set to illustrate would likely help.

In particular, it's difficult to figure see how the 1500x1500 array is to relate to the 4000x1 vector since the values aren't commensurate in size. It could be illustrated with sizes much smaller but representative.

On the off chance you're talking about addressing a column in an array for the 4000, that's simply use of the colon operator and a loop index. If the array is x, then

for i=i:size(x,2)  % over columns in x
  y=x(:,i);        % select the i_th_ column from x...
  ...

[Stefano Alberti]

I've a 4000 matrix of 1500x1500, and it rappresent a displacement. I've a 1 matrix of 4000x1, and it rappresent the time.

I'd create a matrix with each cells its the resulf ot division of first matrix/first value of second matrix.

                e.g.

                  matrix 1 = 1 2 3
                             4 5 6  
                             ...
                  matrix 2 = 7
                             8
                             9
                             10
                             11
                             12
                             ....
                  matrios result = 1/7 2/8 3/9
                                   4/10 5/11 6/12
                                    ...

Do it in a for cycle for each matrix.

It si possible ?

Thanks

[dpb]

Still, 1500 X 1500 ~= 4000??? (Actually, of course, 1500^2 is much, much larger than 4000.)

As for the element-wise division, for the first N elements of the first it's possible...

M=matrix1.';           % reorient to column major
M4K=M(1:4000);         % save first 4K points
matrix2=M4K./matrix2;  % do division as illustrated by example

But, still how to treat the 2.246 million other values from the original 2.25M-element 1500-square array would be a mystery.