Filter löschen
Filter löschen

Info

Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.

MATLAB error 'index exceeds matrix dimensions'

1 Ansicht (letzte 30 Tage)
ali
ali am 4 Feb. 2016
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
hello all
i want to run this function but i got index exceeds, i checked my loops but i could not saw the error.
where vn=vs=1 and M=100 and th1=1000 and Dr1=D1=0
function D=distortion(vn,vs,M,th1,x,y,Dr1,D1);
for i=1:M;
for j=1:M;
if i~=j
d1(i,j)=sqrt(((y(j)-y(i))^2+(x(j)-x(i))^2));
Dr1=exp(-d1(i,j)/th1)+Dr1;
end
end
end
for i=1:M
ds1(i)=sqrt(((y(j)-0)^2+(x(j)-0)^2));% point source at 0 0
cor2=exp(-ds1(i)/th1);
D1=cor2+D1;
end
D=(vs^2)-((vs^4)/(M*((vs^2)+(vn^2))))*(2*(D1-1))+((vs^6)/((M^2)*((vs^2)+(vn^2)))*Dr1);
end

Antworten (1)

Image Analyst
Image Analyst am 4 Feb. 2016
This worked for me.
function test1
vn=1
vs=1 ;
M=100 ;
th1=1000;
Dr1=0;
D1=0
y = rand(1,M);
x = rand(1,M);
D=distortion(vn,vs,M,th1,x,y,Dr1,D1)
end
function D=distortion(vn,vs,M,th1,x,y,Dr1,D1)
for i=1:M;
for j=1:M;
if i~=j
d1(i,j)=sqrt(((y(j)-y(i))^2+(x(j)-x(i))^2));
Dr1=exp(-d1(i,j)/th1)+Dr1;
end
end
end
for i=1:M
ds1(i)=sqrt(((y(j)-0)^2+(x(j)-0)^2));% point source at 0 0
cor2=exp(-ds1(i)/th1);
D1=cor2+D1;
end
D=(vs^2)-((vs^4)/(M*((vs^2)+(vn^2))))*(2*(D1-1))+((vs^6)/((M^2)*((vs^2)+(vn^2)))*Dr1);
end
What did you pass in for X and Y?
  16 Kommentare
Walter Roberson
Walter Roberson am 5 Feb. 2016
You see the importance of showing us the actual error instead of just saying that you get an error somewhere?
ali
ali am 5 Feb. 2016
yes u r right

Diese Frage ist geschlossen.

Tags

Noch keine Tags eingegeben.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by