Deleting duplicate rows and keeping zero rows?

Hi! I need a help!

A=[1 2;
   3 4; 
   0 0;
   1 2; 
   5 6; 
   0 0]

How can i delete duplicate rows, without deleting zero rows? I want my new matrix to look like that:

A=[1 2;
   3 4; 
   0 0; 
   5 6; 
   0 0]

Thank you very much! ;)

Answer 1

[Stephen23]

A=[1 2;
   3 4;
   0 0;
   1 2;
   5 6;
   0 0]

X = ~any(A,2)
[~,Y] = unique(A(~X,:),'rows','stable')
Z = X(~X)
Z(Y) = true
X(~X) = Z
B = A(X,:)

creates this:

B =
   1     2
   3     4
   0     0
   5     6
   0     0

[Karmen]

Thank you 1000 times! I really appreciate your help!;) It works perfectly and the answer is exactly what i was asking for.

Answer 2

[the cyclist]

Here is another way.

zeroRowIndex       = find(~any(A,2)); % Rows with all zeros
[~,uniqueRowIndex] = unique(A,'rows'); % Unique rows (including all-zero rows)

rowsToKeep = union(uniqueRowIndex,zeroRowIndex); % Combine the criteria. [union will discard duplicates by default]
B = A(rowsToKeep,:); % Output

[Karmen]

Works great also! Thank you!