How to rename array layer number or iteration no.

I have an array

 layer1 =

    90    90   -45     0     0    45    45     0   -45
    90    90   -45     0     0    45    45   -45     0
    90    90   -45     0     0    45     0   -45    45
    90    90   -45     0    45    45     0   -45     0
    90    90     0     0    45    45     0   -45   -45
    90   -45     0     0    45    45     0   -45    90

 layer = reshape(layer1(2:end,:)',1,size(layer1,2),(size(layer1,1)-1));

output

layer(:,:,1) =

    90    90   -45     0     0    45    45   -45     0

 layer(:,:,2) =

    90    90   -45     0     0    45     0   -45    45

 layer(:,:,3) =

    90    90   -45     0    45    45     0   -45     0

 layer(:,:,4) =

    90    90     0     0    45    45     0   -45   -45

 layer(:,:,5) =

    90   -45     0     0    45    45     0   -45    90

I'm calculating other values for layer1 and i want to reshape to layer(:,:,6) to layer(:,:,10)

 layer1 =

    90   -45     0     0    45    45     0   -45   90
    90   -45     0     0    45    45   -45     0   90
    90   -45     0     0    45     0   -45    45   90
    90   -45     0    45    45     0   -45     0   90
    90     0     0    45    45     0   -45   -45   90
   -45     0     0    45    45     0   -45    90   90

>

[Guillaume]

Indexing in matlab starts at 1. You don't have a choice.

[Triveni]

Is it not possible to copy array(1:5) to (6:10) ?? or by any other process it could be rename??

[Guillaume]

Well, you can always pad the array with 5 rows of zeros, but honestly I don't see the point.

An index is not a name.

[Triveni]

In case of zeros.

 layer = zeros(1,9,10);

can we allocate/fill values of layer(:,:,1) to layer(:,:,5)?. Is it not possible to refill the values from next loop it should be layer(:,:,6) to layer(:,:,10)??

[Triveni]

I have edited question....please see again

Answer 1

[Andrei Bobrov]

Сan it?

layer1 = circshift(layer1,[0 8]);

or

layer1 = layer1(:,[2:end,1]);

or

p = [90 90 -45 0 0 45 45 0 -45];
idx = fliplr([true, diff(fliplr(p))~=0]);
ii = find(idx);
n = numel(ii);
layer1 = zeros(n,numel(p));
layer1(1,:) = p([2:end,1]);
i1 = fliplr(ii);
for jj = 2:n
    layer1(jj,:) = layer1(jj-1,:);
    layer1(jj,[i1(jj)-1,end-1]) = layer1(jj,[end-1,i1(jj)-1]);
end

[Triveni]

I have edited question....please see again

[Andrei Bobrov]

I'm edited my answer