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index out of bound

1 Ansicht (letzte 30 Tage)
sweta arya
sweta arya am 20 Jan. 2016
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
intial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
y =zeros(30,1);
y = datasample(intial_image,30);
disp(y(2,1));
size3=0;
nBins=8;
Nind=0;
h1=0;
count=0;
for i=1:30
if(numel(y)==30)
jpgFileName = strcat('C:\Users\priya\Desktop\Fashion Photography\',num2str(y(i)), '.jpg');
I= imread(jpgFileName);
[row,col,m]=size(I);
size3=size3+ row*col;
count=count+1;
end
giving error:
can not access y(2,1) because numel(y)=1.
  2 Kommentare
Stephen23
Stephen23 am 20 Jan. 2016
Please show us all of the error message. This means all of the red text.
Stephen23
Stephen23 am 20 Jan. 2016
The code needs to be simplified. Replace this:
initial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
with this:
initial_image = (1:180).';
There is no point in preallocating y like this:
y =zeros(30,1);
because it is completely reallocated on the very next line:
y = datasample(...)

Antworten (1)

Walter Roberson
Walter Roberson am 20 Jan. 2016
Whatever
datasample(intial_image,30)
is, it is resulting in a scalar.
What is the result of
which -all datasample
? Is it from the Statistics Toolbox or does it resolve to one of your own routines?

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