Sort a matrix with respect to a date.
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Marty Dutch
am 17 Sep. 2015
Bearbeitet: Stephen23
am 17 Sep. 2015
Hi experts, is there a way to sort variables in a matrix based on date? For instance, here I want to first sort the variables based on column 3 (0s first then 1s) and then based on date (earliest dates first). See for an example below.
list =
{3436x1 cell} [3436x11 char] [3436x1 double]
'BG4704_01' 03-Jan-2015 0
'BG4705_01' 02-Jan-2015 1
'BG4706_01' 21-Dec-2014 0
'BG4707_01' 23-Oct-1913 1
'BG4708_01' 05-Jul-1913 1
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Stephen23
am 17 Sep. 2015
Bearbeitet: Stephen23
am 17 Sep. 2015
Probably the easiest way is to simply convert those date strings to date numbers, which can then be sorted together with the binary values:
% original data in X
X{1} = {'BG4704_01';'BG4705_01';'BG4706_01';'BG4707_01';'BG4708_01'};
X{2} = ['03-Jan-2015';'02-Jan-2015';'21-Dec-2014';'23-Oct-1913';'05-Jul-1913'];
X{3} = [0;1;0;1;1];
% create numeric matrix Y and sort based on binary then dates:
Y(:,2) = datenum(X{2},'dd-mmm-yyyy');
Y(:,1) = X{3};
[~,idx] = sortrows(Y)
% rearrange data inside cell vector X
for k = 1:numel(X)
X{k} = X{k}(idx,:);
end
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