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If loop using cell arrays

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Bas
Bas am 14 Sep. 2015
Kommentiert: Titus Edelhofer am 14 Sep. 2015
Hi,
I have 2 matrices:
A with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) defining salaries
B with 24 arrays of each different length (i.e. A{1} 2362x1, A{2} 2341x1) contains either a 0 or a 1
And last I have 2 boundary values C= 2600 and D= 1700.
I want to check the following:
if B(each value) == 0 && A(each value) > C
A(this value)= C
elseif B(each value) == 1 && A(each value) > D
A(this value)= D
end
Can anyone help me out?
  1 Kommentar
Walter Roberson
Walter Roberson am 14 Sep. 2015
There is no such thing as an "if loop". There are "for loop" and there are "while loop" and there are "if statement". A loop would have to execute its body multiple times, but "if" executes the body only 1 time or 0 times.

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Guillaume
Guillaume am 14 Sep. 2015
You don't need any if. Just use logical operations. Your first condition is to replace elements when B is false (i.e. B==0 or simply ~B) and A greater than C, so is simply writen as A(~B & A>C). Similarly your second condition is simply A(B==1 & A>D) (which simplifies to A(B & A>D). You just have to apply that to each cell of the cell arrays:
for cellidx = 1:numel(A)
a = A{cellidx};
b = B{cellidx};
a(~b & a>C) = C;
a(b & a>D) = D;
A{celldix} = a;
end
  1 Kommentar
Bas
Bas am 14 Sep. 2015
Thanks Guillaume, this is what I was searching for!

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Titus Edelhofer
Titus Edelhofer am 14 Sep. 2015
Hi,
I'm not 100% sure I understand what you want to do, but I guess it should be like this
for i=1:length(A)
if all(B{i}(:)==0 & A{i}(:)>C)
A{i}(:) = C;
elseif all(B{i}(:)==1 & A{i}(:)>D)
A{i}(:) = D;
end
end
Titus
  4 Kommentare
Guillaume
Guillaume am 14 Sep. 2015
Bearbeitet: Guillaume am 14 Sep. 2015
Both codes have the following preconditions:
assert(isequal(numel(A), numel(B)));
assert(all(cellfun(@(a,b) isequal(size(a), size(b)), A, B)));
Titus Edelhofer
Titus Edelhofer am 14 Sep. 2015
I wish I could vote for a comment! Nice assert calls.

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