Ältere Kommentare anzeigen
i have a simple ques that if i have z-plane having x and y axes,and i express z=x+i*y,and x if fixed let say 5 any y=0:10 then how can i plot this thing,please guide me,i m waiting for reply
1 Kommentar
Muhammad Usman
am 12 Dez. 2011
Antworten (3)
bym
am 11 Dez. 2011
y = 1:10;
x=5*ones(size(y));
z=x+i*y;
plot(real(z),imag(z))
1 Kommentar
Walter Roberson
am 11 Dez. 2011
That will not be able to show the values of x and y on the axes.
Mohsen Davarynejad
am 11 Dez. 2011
y = [0:.1:10]
plot(5,y)
xlabel('Re')
ylabel('Im')
3 Kommentare
Walter Roberson
am 11 Dez. 2011
What about z? y is not the imaginary quantity.
My recollection is that if you plot a scalar x against a row vector y, that you end up with a single (probably invisible) point, but that if you plot a scalar x against a column vector y, you will get a line. It is, my memory says, an exception to the "row vector is automatically converted to column vector" rule, and happens because the size of x (i.e., one) happens to match the first dimension of y (i.e., one for a row vector)
Mohsen Davarynejad
am 11 Dez. 2011
If z = x + yi, then x is the "real part" and y is the "imaginary part". When x is a constant and y is vector, then you will have line in the complex plane. No?
http://en.wikipedia.org/wiki/Imaginary_number
Walter Roberson
am 12 Dez. 2011
z might be a line in the complex plane, but plot(5,y) does not involve z at all, and plot(5,z) would be refused because it is not allowed to plot complex data except through plot(z) which in turn is the same as plot(real(z),imag(z)) -- real vs imaginary.
Walter Roberson
am 11 Dez. 2011
y = 0:10;
x = 5 * ones(size(y));
z = x + i * y;
Now, if "i" were a real-valued constant, you would then use
plot3(x, y, z)
However, "i" is the complex constant, so you have a line in complex space, and there is no way to draw that in one step. Instead you would need to use something like,
plot3(x, y, real(z), 'r', x, y, imag(z), 'g', x, y, abs(z), 'b')
or perhaps plot 3 separate images using subplot()
1 Kommentar
Muhammad Usman
am 12 Dez. 2011
Kategorien
Mehr zu Special Functions finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!