Calculation of Phi value in matlab
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unknown777
am 25 Aug. 2015
Kommentiert: unknown777
am 26 Aug. 2015
width=20;
length=40;
height=10;
x=1:2:20;
y=1:4:40;
z=1:1:10;
E =length/width;
alpha=atan(E);
x1= (x.*sin(alpha)) - (y .* cos (alpha));
y1= (height./2)-z;
k= y1 ./ x1;
phi1=zeros(size(k));
for ii= 1:length(k)
if k(ii)>0
phi1(ii)= atan(k(ii)); % equation 1
else
phi1(ii)= pi-atan(k(ii)); % equation 2
end
end
Error msg : ??? Subscript indices must either be real positive integers or logicals.
Sorry. I am very noob at matlab. Please help me correct with the error. I am trying to calculate the phi1 value. When k is positive it have to use the quation 1 and when k is negative it have to use the equation 2.
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Akzeptierte Antwort
maria
am 25 Aug. 2015
Try:
width=20;length=40;height=10;
x=1:2:20;
y=1:4:40;
z=1:1:10;
E =length/width;
alpha=atan(E);
x1= (x.*sin(alpha)) - (y .* cos (alpha));
y1= (height./2)-z;
k= y1 ./ x1;
[M,N]=size(k)
phi1=zeros(N);
for ii= 1:N
if k(ii)>0 phi1(ii)= atan(k(ii)); % equation 1 else phi1(ii)= pi-atan(k(ii)); % equation 2
end
end
Weitere Antworten (1)
Image Analyst
am 25 Aug. 2015
This error is very well explained by the FAQ: http://matlab.wikia.com/wiki/FAQ#How_do_I_fix_the_error_.22Subscript_indices_must_either_be_real_positive_integers_or_logicals..22.3F After reading that, you will know what to do.
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