Using Values from an image array in an equation to give a new image

1 Ansicht (letzte 30 Tage)
Hi there, I have two images arrays that I want to ratio in an equation to give a new image T however I am having problems doing this.
AvgImg1 = uint16(zeros(1024,1280)); AvgImg1 Values
AvgImg2=uint16(zeros(1024,1280)); AvgImg2 Values
K1=imagesc((AvgImg1));
K2=imagesc((AvgImg2));
T=uint16(zeros(1024,1280)
T=constant*ln(K1/K2);
plot T

Akzeptierte Antwort

Image Analyst
Image Analyst am 21 Aug. 2015
So what do you think 0/0 should give? Also, don't make them integer if you're going to divide them. And use imshow(T, []) instead of plot() to display the resulting image. And you don't need to preallocate T in this case.
  2 Kommentare
Robert Roy
Robert Roy am 21 Aug. 2015
Its not 0/0, sorry thats just to setup the arrary. How would I go about not making it integer if i was not to divide them? Thanks
Image Analyst
Image Analyst am 21 Aug. 2015
Don't use K1 and K2 at all - they're just handles to the images, not the images themselves which are called AvgImg1 and AvgImg2. Cast them to double or else you will get an integer divide and the quotient will be either 0 or 1. Then use ./ instead of / to do an element by element divide.
AvgImg1 = uint16(zeros(1024,1280)); %AvgImg1 Values
AvgImg2=uint16(zeros(1024,1280)); % AvgImg2 Values
subplot(2,2,1);
imshow(AvgImg1);
subplot(2,2,2);
imshow(AvgImg2);
T=constant*ln(double(AvgImg1) ./ double(AvgImg2));
subplot(2,2,3);
imshow(T, []);

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Image Processing Toolbox finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by