How to add zeros to 2 x vectors where there are no matches, to get the same length ?
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Joel Sande
am 29 Jul. 2015
Bearbeitet: Stephen23
am 30 Jul. 2015
x=[1 2 3 4];
y=[1 2 3 1];
x1=[3 4 5 6 7 8];
y1=[2 6 4 2 5 3];
[x, y, x1, y1] = Tout_Ajuster(x, y, x1, y1)
I want to put zeros where there is no match in x axes to get the same length for (x and x1) so I write a small code (Tout_Ajuster.m) in the output, x1 misses (5 and 6) so y1 miss(4 and 2) What is missing in my function < Tout_Ajuster.m > ???
2 Kommentare
Jon
am 29 Jul. 2015
It would help if you gave us the expected outputs for x1 and y1. Otherwise it's not clear what you're trying to do.
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Jon
am 29 Jul. 2015
Your question seems ambiguous to me, but based off my interpretation, see if this code gives you the result you're looking for:
% This assumes that none of the matching x values are 0
N = max(numel(x),numel(x1));
xout = zeros(1,N);
yout = zeros(1,N);
x1out = zeros(1,N);
y1out = zeros(1,N);
% Reinsert the known values of x and y
xout(1:numel(x)) = x;
yout(1:numel(y)) = y;
% Values in x1 (and the correponding y1 positions) that do not appear in x are set to zero
for i = 1:numel(x)
matching = find(x(i) == x1);
if isempty(matching) == 1
continue
else
x1out(matching) = x1(matching);
y1out(matching) = y1(matching);
end
end
Gives the following results:
xout =
1 2 3 4 0 0
yout =
1 2 3 1 0 0
x1out =
3 4 0 0 0 0
y1out =
2 6 0 0 0 0
1 Kommentar
Azzi Abdelmalek
am 29 Jul. 2015
n=max(numel(x),numel(x1))
x=[x zeros(1,n)]
x1=[x1 zeros(1,n)]
y=[y zeros(1,n)]
y1=[y1 zeros(1,n)]
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