How to convert cell array to structure array
14 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Aleksandar
am 13 Jun. 2015
Kommentiert: Stephen23
am 23 Jul. 2016
I would like to convert cell array to a structure 1x2 (or 2x1) with 3 fields with a1 as dimension/axis:
a1={'AA','AA','AA','BB','BB','BB','BB'}';
a2={'35000','96000','88000','33000','44000','8000','18000'}';
a3={'1a','1b','1c','1d','1e','1a','1b'}';
a123=[a1,a2,a3];
rowHeadings = {'first', 'second', 'third'};
but this does not work:
depts = cell2struct(a123, rowHeadings, 1)
Error using cell2struct
Unknown command option.
7 Kommentare
Stephen23
am 15 Jun. 2015
Bearbeitet: Stephen23
am 15 Jun. 2015
@Aleksandar: it looks like you are a bit confused about what structures can do. Structures are not really categorization tools, nor are they dictionaries (which might look similar to what you wrote above). Like most traditional MATLAB data classes the dimensions of a structure do not encode any meta-data, so you cannot "name" the dimensions of a 1x2 structure 'AA' and 'BB', atleast not as meta-data in the structure itself. It would be possible to either:
- create a separate array containing this data, or
- include this meta-data as data withing the structure (see my answer below).
- use another data class: it seems like you might really be looking for something more like a table. Have you looked at using one?
Vahab Youssofzadeh
am 22 Jul. 2016
Try the following:
table2struct(cell2table(.))
Akzeptierte Antwort
Azzi Abdelmalek
am 13 Jun. 2015
a1={'AA','AA','AA','BB','BB','BB','BB'}';
a2={'35000','96000','88000','33000','44000','8000','18000'}';
a3={'1a','1b','1c','1d','1e','1a','1b'}';
a123=[a1,a2,a3];
rowHeadings = {'first', 'second', 'third'};
v=cell2struct(a123,rowHeadings,2)
3 Kommentare
Azzi Abdelmalek
am 15 Jun. 2015
a1={'AA','AA','AA','BB','BB','BB','BB'}';
a2={'35000','96000','88000','33000','44000','8000','18000'}';
a3={'1a','1b','1c','1d','1e','1a','1b'}';
a123=[a1,a2,a3];
rowHeadings = {'first', 'second', 'third'};
ii=unique(a1)
for k=1:numel(ii)
idx=ismember(a1,ii{k})
v(k).first=ii{k}
v(k).second=a2(idx)
v(k).third=a3(idx)
end
Stephen23
am 15 Jun. 2015
Note that it is poor practice in MATLAB to expand arrays inside loops, even for structures and cell arrays:
It is better either to create the entire structure in one call (see my answer), or to preallocate the structure (e.g. looping in reverse).
Weitere Antworten (1)
Stephen23
am 15 Jun. 2015
Bearbeitet: Stephen23
am 15 Jun. 2015
a1 = {'AA','AA','AA','BB','BB','BB','BB'}';
a2 = {'35000','96000','88000','33000','44000','8000','18000'}';
a3 = {'1a','1b','1c','1d','1e','1a','1b'}';
hdr = {'first', 'second', 'third'};
fun = @(x)arrayfun(@(s)x(strcmp(s,a1)), unique(a1,'stable'), 'UniformOutput',false);
X = struct(hdr{1},fun(a1), hdr{2},fun(a2), hdr{3},fun(a3));
Now lets check it in the command window:
>> X
X =
2x1 struct array with fields:
first
second
third
>> X.first
ans =
'AA'
'AA'
'AA'
ans =
'BB'
'BB'
'BB'
'BB'
>> X.second
ans =
'35000'
'96000'
'88000'
ans =
'33000'
'44000'
'8000'
'18000'
2 Kommentare
Stephen23
am 23 Jul. 2016
"I suppose it refers to both answers"
No, it doesn't. You can vote for other answers though.
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!