matrix columns and rows manipulating with loop
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am 5 Jun. 2015
Beantwortet: Guillaume
am 5 Jun. 2015
n=6; %which is variable, the number of vector's dimension.
i=1:(n-3);
u=cos(i-3);
u=u(:);
jn=(2*cos(u(i)));
% I need to create below arrays with loop w.r.t. the "n" and "jn";
column_1=[0;0;0;jn(1);0;0]; %number of columns is equal (n-3)
column_2=[0;0;0;0;jn(2);0];
column_3=[0;0;0;0;0;jn(3)];
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Guillaume
am 5 Jun. 2015
No need for loop. You're also better off keeping your 3 columns as one matrix rather than making individually numbered variables.
m = [zeros(n-3, 3); diag(jn)]
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