Iterating to Find the max value
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi, I am trying to find the maximum value of "Fm" that can be outputted from the programme. The programme is iterating from 1 through 359 degrees for that formula.
I know that i can just output all of the numbers and physically find which one is largest, but is there some sort of "if" statement I can make that will find it for me automatically?
Here is my code:
maxangle=359;
for muscleangle=1:maxangle;
a=0.15;
b=0.3;
c=0.6;
W=40;
Wo=60;
Fmy=(b*W+c*Wo)/a;
Fm=Fmy/sind(muscleangle);
Fmx=Fm*cosd(muscleangle);
disp (Fm);
disp(muscleangle);
end
I would really appreciate any help.
Thanks
0 Kommentare
Antworten (3)
Andrei Bobrov
am 21 Nov. 2011
muscleangle = 1:360;
a=0.15;
b=0.3;
c=0.6;
W=40;
Wo=60;
Fmy=(b*W+c*Wo)/a;
Fm=Fmy./sind(muscleangle);
Fmx=Fm.*cosd(muscleangle);
out = max(Fm(isfinite(Fm)))
Jan
am 21 Nov. 2011
a=0.15;
b=0.3;
c=0.6;
W=40;
Wo=60;
Fmy=(b*W+c*Wo)/a;
Fm_max = -Inf;
for muscleangle=1:359
Fm = Fmy / sind(muscleangle);
Fmx = Fm * cosd(muscleangle);
if Fm > Fm_max % Or Fmx? [EDITED: FM_max->Fm_max]
Fm_max = Fm;
disp(Fm);
disp(muscleangle);
end
end
2 Kommentare
Jan
am 21 Nov. 2011
@Stephen: This is a typo obviously. I think, it would not be to hard to find out, that I've written "Fm_max" at first and "FM_max" afterwards. But both need the same name.
I've interpreted "just output all of the numbers and physically find which one is largest" such that you know how to solve this using MAX already. Therefore I've posted the less efficient loop method using IF.
Daniel Shub
am 21 Nov. 2011
a=0.15;
b=0.3;
c=0.6;
W=40;
Wo=60;
Fmy=(b*W+c*Wo)/a;
Fm_max = -Inf;
muscleangle=1:359;
Fm = Fmy./sind(muscleangle);
Fmx = Fm.*cosd(muscleangle);
Fm_max = max(Fm)
0 Kommentare
Siehe auch
Kategorien
Mehr zu Digital Filter Analysis finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!