My GUI have 81 TextAreas. The names are indexed, e.g. A1TextArea and A2TextArea.
App.A1TextArea.Value = 1 changes A1TextArea to 1
What is the code to change the Nth TextArea programatically? N is a variable
App.A+'n'+TextArea.Value = 1

1 Kommentar

Stephen23
Stephen23 am 2 Apr. 2025
Rather than using pseudo-indices in text, why not use actual indices? Then your task is achieved using basic indexing.

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Walter Roberson
Walter Roberson am 2 Apr. 2025
Bearbeitet: Walter Roberson am 2 Apr. 2025

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for n = 1 : 81
App.("A" + n + "TextArea").Value = 1
end
That said, it is better to create an array of text areas instead of naming them each individually. With an array of text boxes you could do
set(App.TextAreas, 'Value', 1)
to set the Value property of all of the TextAreas at the same time.

1 Kommentar

Rick
Rick am 3 Apr. 2025
Thanks for the answer! It is working. I see your point. I have to learn how to create an array of text boxes to simplify the code.

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Steven Lord
Steven Lord am 2 Apr. 2025

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While you can access property names dynamically as stated in the "Reference Properties Using Variables" section of this documentation page:
R = RandStream.getGlobalStream;
R.Type % Accessing a property using a name known when the code is written
ans = 'mt19937ar'
name = 'Type';
R.(name) % Accessing a property using a name that could vary at run-time
ans = 'mt19937ar'
In this case I'd consider using one property that contains an array of handles. With that you can index into an element of the array to access a particular handle.
f = figure(Color = 'r');
textObjectHandles = gobjects(2);
for k = 1:4
textObjectHandles(k) = uicontrol(Style='text', Units='normalized', ...
Position=[0.1 0.2*k 0.5 0.1], String = string(k));
end
textObjectHandles
textObjectHandles =
2x2 UIControl array: UIControl UIControl UIControl UIControl
textbox3 = textObjectHandles(1, 2)
textbox3 =
UIControl (3) with properties: Style: 'text' String: '3' BackgroundColor: [0.9400 0.9400 0.9400] Callback: '' Value: 0 Position: [0.1000 0.6000 0.5000 0.1000] Units: 'normalized' Use GET to show all properties

1 Kommentar

Rick
Rick am 3 Apr. 2025
I don't think I follow you. I resolved my problem with the first answer though. Thanks for taking the time to answer me. I appreciate.

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