Unzip to a cell array, get the csv filles
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
HI I unzip a file to a cell
unzipfile =
10×1 cell array
{'2025-01-28/' }
{'2025-01-28/KBIS_V06_20250128_000621.csv'}
{'2025-01-28/KBIS_V06_20250128_001320.csv'}
{'2025-01-28/KBIS_V06_20250128_002007.csv'}
{'2025-01-28/KBIS_V06_20250128_002713.csv'}
{'2025-01-28/KBIS_V06_20250128_003412.csv'}
{'2025-01-28/KBIS_V06_20250128_004111.csv'}
{'2025-01-28/KBIS_V06_20250128_004816.csv'}
{'2025-01-28/KBIS_V06_20250128_005509.csv'}
{'2025-01-28/KBIS_V06_20250128_010208.csv'}
}
How can I get the content of the csv files? I woul like to avoid use unzip command to a folder I need a fast solution becaus I have lots of zip files containing hundrets of csv.
0 Kommentare
Akzeptierte Antwort
Stephen23
am 11 Mär. 2025
Bearbeitet: Stephen23
am 11 Mär. 2025
"I got Error using readtable Unable to find or open '2025-01-28/'. Check the path and filename or file permissions."
You get an error because a folder is not a file, yet you are trying to call FOPEN/READTABLE on a folder (the CSV files are stored in a folder, which UNZIP returns as the first element of the output cell array). Use ISFILE or similar to ignore any folders:
P = './mysub'; % absolute/relative path to where the files are unzipped to
C = unzip('2025-03-11.zip',P) % note the first element is NOT a filename!
dir(C{1})
C(~cellfun(@isfile,C)) = []; % remove folder names
D = C;
for k = 1:numel(C)
F = C{k};
T = readtable(F);
D{k} = T;
end
All of the imported data is in the cell array D
D{:}
vertcat(D{:})
Depending on the existence of other files, you might also be able to use DIR.
0 Kommentare
Weitere Antworten (2)
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!