Fast reorganization of cell arrays
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Christopher Smith
am 15 Feb. 2025
Kommentiert: Stephen23
am 6 Apr. 2025
I have two cell arrays which store row indices to other arrays for processing. TB is a column cell array that stores the indices for all of the "targets" that interact with "sources" in the SB column cell array. The cell index of TB corresponds to the same cell index of SB. In other words, all of the indices in TB{1} interact with all of the indices in SB{1}. I would like to out of TB all of the unique indices, then find all of the indices in SB that interact with each unique index in TB. The tricky bit is that some of the indices in TB are repeated across cells. I have included a minimum working example that does what I want. It runs quickly enough for small arrays, but becomes slow when the TB and SB arrays/cells get large. Is there a way to make this faster and more compact? Thank you for any insight!
% build the two arrays
TB = cell(3,1); % "target" array
TB{1} = [1;2;3;4;5];
TB{2} = [4;5;6];
TB{3} = [7,8,9,10];
SB = cell(3,1); % "source" array
SB{1} = (1:1:15)';
SB{2} = (16:1:30)';
SB{3} = (31:1:45)';
% build the intermediate sorted array
NTB = length(TB);
out1 = []; % intermediate array
for cnt = 1:NTB
for cnt2 = 1:length(TB{cnt})
out1 = [out1;repmat(TB{cnt}(cnt2),size(SB{cnt},1),1),SB{cnt}];
end
end
% pull out of the intermediate array the desired arrays
TB_desired = unique(out1(:,1)); % all of the unique "targets"
NTB_desired = length(TB_desired);
SB_desired = cell(NTB_desired,1);
for cnt = 1:NTB_desired
logvar = TB_desired(cnt) == out1(:,1);
SB_desired{cnt} = out1(logvar,2); % all of the "sources" that interact with each unique "target"
end
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Stephen23
am 15 Feb. 2025
Bearbeitet: Stephen23
am 15 Feb. 2025
The timings might be similar for small arrays, but try testing on larger arrays!
tic
% Initialize target and source arrays
tgt = {[1;2;3;4;5],[4;5;6],[7,8,9,10]};
src = {(1:15).',(16:30).',(31:45).'};
% Preallocate the intermediate array for better performance
len = sum(cellfun(@numel,tgt) .* cellfun(@numel,src));
arr = zeros(len,2);
% Build the intermediate array more efficiently
idx = 1;
for ii = 1:numel(tgt)
val = tgt{ii}(:); % Ensure column vector
dat = src{ii};
% Calculate indices for current block:
num = numel(val) * numel(dat);
pos = idx:(idx+num-1);
% Create pairs using vectorized operations:
[tmp,raw] = ndgrid(val,dat);
arr(pos,:) = [tmp(:),raw(:)];
%
idx = idx + num;
end
% Create final mapping:
[tgx,~,ids] = unique(arr(:,1));
out = accumarray(ids,arr(:,2),[],@(x){x});
toc
SB_desired1 = out
Compared with your original code:
tic
% build the two arrays
TB = cell(3,1); % "target" array
TB{1} = [1;2;3;4;5];
TB{2} = [4;5;6];
TB{3} = [7,8,9,10];
SB = cell(3,1); % "source" array
SB{1} = (1:1:15)';
SB{2} = (16:1:30)';
SB{3} = (31:1:45)';
% build the intermediate sorted array
NTB = length(TB);
out1 = []; % intermediate array
for cnt = 1:NTB
for cnt2 = 1:length(TB{cnt})
out1 = [out1;repmat(TB{cnt}(cnt2),size(SB{cnt},1),1),SB{cnt}];
end
end
% pull out of the intermediate array the desired arrays
TB_desired = unique(out1(:,1)); % all of the unique "targets"
NTB_desired = length(TB_desired);
SB_desired0 = cell(NTB_desired,1);
for cnt = 1:NTB_desired
logvar = TB_desired(cnt) == out1(:,1);
SB_desired0{cnt} = out1(logvar,2); % all of the "sources" that interact with each unique "target"
end
toc
SB_desired0
isequal(SB_desired0,SB_desired1)
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