how to sort histogram generated count and corresponding gray value.. pls help
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ARJUN K P
am 18 Mai 2015
Kommentiert: Image Analyst
am 20 Mai 2015
m=imread('ll.bmp');
[count,gray]=imhist(m);
the answer is:

i want to sort the count and corresponding gray value..
and delete the zero count values answer like this..

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ARJUN K P
am 20 Mai 2015
Bearbeitet: ARJUN K P
am 20 Mai 2015
1 Kommentar
Image Analyst
am 20 Mai 2015
It does the same thing that I did but combined the counts and gray level arrays into a single 2D array (which we didn't know you wanted to do).
Weitere Antworten (2)
Image Analyst
am 18 Mai 2015
Don't use gray as a variable name - it's the name of a built in function that creates a colormap, and you just blew it away.
I don't know why you need to, but to get rid of array elements with zero counts
[count, grayLevels]=imhist(m);
rowsToDelete = count == 0;
count(rowsToDelete) = [];
grayLevels(rowsToDelete) = [];
5 Kommentare
Image Analyst
am 18 Mai 2015
To sort in reverse order, simply use fliplr()
count = fliplr(count)
grayLevels = fliplr(grayLevels);
Image Analyst
am 19 Mai 2015
% Sort count in descending order.
[sortedCounts, sortIndexes] = sort(count, 'descend');
% Sort grayLevels the same way.
grayLevels = grayLevels(sortIndexes);
Siehe auch
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