.what will be change in program if we varying h2 from 1e-3 to 1e-6 pl provide the solution.plot h2(x axis) vs x(real or x imaginary)

% Given values
n1 = 1.521;
n2 = 2.66;
k0 = 1;
h1 = 1.5e-6;
h2 = 1e-6;
ns = 1.512;
nc = 1.2 - 1i*7;

% Define symbolic variable for x
syms x

% Calculate k1 and k2
k1 = sqrt(n1^2 * k0^2 - x^2);
k2 = sqrt(n2^2 * k0^2 - x^2);

% Define M1 and M2 matrices
M1 = [cos(k1 * h1), 1i * sin(k1 * h1) / k1;
    1i * k1 * sin(k1 * h1), cos(k1 * h1)];

M2 = [cos(k2 * h2), 1i * sin(k2 * h2) / k2;
    1i * k2 * sin(k2 * h2), cos(k2 * h2)];

% Multiply matrices to get M
M = M1 * M2;

% Extract elements from M
m11 = M(1,1);
m12 = M(1,2);
m21 = M(2,1);
m22 = M(2,2);

% Define gs and gc
gs = x^2 - ns^2 * k0^2;
gc = x^2 - nc^2 * k0^2;

% Define the function f(x)
f = 1i * (gs * m11 + gc * m22) - m21 + gs * gc * m12;

% Use vpasolve for numerical solution
x_solution = vpasolve(f == 0, x);

% Display the solutions
disp('Numerical solutions for x:')
disp(x_solution)

[John D'Errico]

Ok. So you have the code. Using a loop, vary h2. See what happ[ens. Plot the result. What is the problem?

After having asked 99 questions, many of them multiple times, surely you can use a loop, and we do not need to write the code for you?

[shiv gaur]

the problem is reseach based exact fig is not mathching.If we vary the value of h2 from 1e-3 to 1e-6 then plot the graph

h2 vs x(real) or h2 vs x(imaginary) if any one have answer pl give response

[Walter Roberson]

What we are given is some particular code. Since we do not have any other information about the problem, the given code defines the problem. The solution to the given problem is that, by definition, the given code is perfect and does exactly what it is intended to do. Any error messages produced by the given code must have been intended.

If we had been given the equations or a link to the research paper, then it would have been different.