Any array (let's consider only 2D here) can be indexed using colon operator such
array(p1:p2,p3:p4)
How can one generate list of linear indices (for that particular array) from parameters [p1, p2, p3, p4]?

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Matt J
Matt J am 14 Nov. 2024

1 Stimme

[I,J]=ndgrid(p1:p2,p3:p4);
linear=sub2ind(size(array) , I,J);

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Steven Lord
Steven Lord am 14 Nov. 2024

1 Stimme

See sub2ind.

2 Kommentare

Stephen23
Stephen23 am 14 Nov. 2024
Bearbeitet: Stephen23 am 15 Nov. 2024
Note that in general p1:p2 and p3:p4 when used a indices like that will refer to a rectangular block of that array. So in order to get the linear indices of the entire block you will need to provide SUB2IND with subscript indices for the entire block. One way to achieve this is using NDGRID:
array = randi(9,9,9);
p1 = 3;
p2 = 5;
p3 = 2;
p4 = 5;
[X,Y] = ndgrid(p1:p2,p3:p4);
Z = sub2ind(size(array),X,Y);
array(Z)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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array(p1:p2,p3:p4)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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sub2ind() processes the indexes in parallel. All of the indices must be the same size (or else scalars)
sub2ind([4 5],1:2,1:3)
Error using sub2ind (line 61)
Subscript arguments must be scalars or arrays of the same size.

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Catalytic
Catalytic am 14 Nov. 2024
Bearbeitet: Catalytic am 14 Nov. 2024

0 Stimmen

K=createArray(size(array),Fill=sparse(0));
K(p1:p2,p3:p4)=1;
out=find(K); %linear indices

1 Kommentar

I would probably do instead,
K=createArray(size(array),Fill=sparse(false));
or maybe just use,
K=false(size(array))
depending on the expected size of the output.

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am 14 Nov. 2024

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am 15 Nov. 2024

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