problem with vpa and symsum
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george veropoulos
am 12 Nov. 2024
Verschoben: Stephen23
am 19 Nov. 2024
Hi i make the fumtiom
function z= Escattheory(r,phi)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
syms kk
[f,N,Nc,a,ra,k0,Z0] = parameter();
E0=1;
Z1=k0.*r;
Z2=k0.*ra;
factor1=besselj(kk,Z2).*besselh(kk,2,Z1)./besselh(kk,2,Z2)
factor2=(-1j).^kk.*cos(kk.*phi)
factor=-E0.*factor1.*factor2.*en(kk);
%z=vpa(symsum(factor,k,0,inf),3)
f_all=symsum(factor,kk,0,300);
y=vpa(f_all,3)
end
when i call the function Escattheory(r,phi) with argument r=ra=1 and phi =0 the resultas is - 1.22 + 5.05e-5i
if i use the sum like this
function z= Escattheory_test(r,phi)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
Escattheory_test(r,phi)
function y=Escattheory_test(r,phi)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
[f,N,Nc,a,ra,k0,Z0] = parameter();
E0=1;
Z1=k0.*r;
Z2=k0.*ra;
kk=0:200
factor1=besselj(kk,Z2).*besselh(kk,2,Z1)./besselh(kk,2,Z2)
factor2=(-1j).^kk.*cos(kk.*phi)
factor=-E0.*factor1.*factor2.*e_n(kk);
%z=vpa(symsum(factor,k,0,inf),3)
y=sum(factor)
end
the reuslts is -1-j0 what happen ??
thank you
2 Kommentare
Akzeptierte Antwort
Torsten
am 13 Nov. 2024
Verschoben: Torsten
am 13 Nov. 2024
The numerical bessel functions are not able to compute your sum correctly (for higher values of k, they return NaN) (see below). That's the reason why you get different results.
r = 1;
phi = 0;
Escattheory(r,phi)
Escattheory_test(r,phi)
function z= Escattheory(r,phi)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
syms kk
[f,N,Nc,a,ra,k0,Z0] = parameter();
E0=1;
Z1=k0.*r;
Z2=k0.*ra;
factor1=besselj(kk,Z2).*besselh(kk,2,Z1)./besselh(kk,2,Z2);
factor2=(-1j).^kk.*cos(kk.*phi);
factor=-E0.*factor1.*factor2.*e_n(kk)
%z=vpa(symsum(factor,k,0,inf),3)
f_all=symsum(factor,kk,0,300);
z=vpa(f_all,3);
end
function y=Escattheory_test(r,phi)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
[f,N,Nc,a,ra,k0,Z0] = parameter();
E0=1;
Z1=k0.*r;
Z2=k0.*ra;
kk=0:300;
factor1=besselj(kk,Z2).*besselh(kk,2,Z1)./besselh(kk,2,Z2);
factor2=(-1j).^kk.*cos(kk.*phi);
factor=-E0.*factor1.*factor2.*en(kk)
%z=vpa(symsum(factor,k,0,inf),3)
y=sum(factor);
end
function [f,N,Nc,a,ra,k0,Z0] = parameter()
%UNTITLED Summary of this function goes here
c0=3e8;
Z0=120.*pi;
ra=1;
a=0.92;
N=30;
Nc=30;
f=300e6;
lambda=c0./f;
k0=2*pi./lambda;
end
function y=en(k)
if k==0
y=1;
else
y=2;
end
end
function y=e_n(k)
y = piecewise(k==0,1,k~=0,2);
end
13 Kommentare
Torsten
am 14 Nov. 2024
Bearbeitet: Torsten
am 14 Nov. 2024
As said, I don't know precisely why "piecewise" works with the symbolic solution while your if-construct gives a wrong answer.
My guess is that your function "e_n" is called with a symbolic (unspecified) variable (kk) that is not identified as "0" (which would give 1 for y), but as "else" (which always gives 2 for y).
But you might want to contact MATLAB support for a definite answer:
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