loop over nested functions overwrites variables

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Julia
Julia am 11 Mai 2015
Kommentiert: Julia am 13 Mai 2015
I have written a routine for image processing and want to get the same output for a stack of pictures in the format (:,:,i) with i being the number of the picture (e.g. picture number 30 to 35). However, the output will only have information for the final i(:,:,35) and (:,:,30) to (:,:,34) will be empty, that is they have been overwritten. I tried a smaller loop to get the idea
zMin=30; zMax=35;
while zMin <= zMax
for i = zMin
a(1,1,i)=zMin
zMin=zMin+1;
end;
end;
and here it works perfectly fine. However, in my code consisting of nested functions, it doesn't, so I assume it has something to do with the format of the code:
function [firstScanRaw, mask, maskedImage, Ipores, Iskeleton, PropsLCCP, PropsLCCS, PoresBackbone, SkeletonBackbone, Porosity, Skeleton, nPixelROI, SkeletonObjects, PoreObjects, EulerRealisationsSkeleton, EulerRealisationsPores,PoreWidthRealisations, SkelWidthRealisations ] = porous_main(sampleName, zMin, zMax, display);
[firstScanRaw] = porous_load_input (sampleName,zMin);
[mask, maskedImage] = porous_polygon (firstScanRaw, display, sampleName);
while (zMin <= zMax)
for i = zMin;
[firstScanRaw] = porous_load_input (sampleName,zMin);
[mask, maskedImage] = porous_polygon_choosen (firstScanRaw, display, sampleName, mask,i);
[Ipores, Iskeleton] = porous_binarisation (maskedImage, display,i);
[PropsLCCP, PropsLCCS] = porous_elements(Ipores, Iskeleton, display, i);
[PoresBackbone, SkeletonBackbone, Porosity, Skeleton, nPixelROI, PoreDist, SkelDist] = porous_sizes (Iskeleton, Ipores, display, mask, maskedImage,i);
[Porosity, Skeleton, SkeletonObjects, PoreObjects, EulerRealisationsSkeleton, EulerRealisationsPores, PoreWidthRealisations, SkelWidthRealisations ] = porous_output(Porosity, Skeleton, PoreDist, SkelDist,PoresBackbone, SkeletonBackbone, nPixelROI, sampleName, PropsLCCP, PropsLCCS,i);
zMin=zMin+1;
end;
end;
end
  3 Kommentare
Stephen23
Stephen23 am 11 Mai 2015
Bearbeitet: Stephen23 am 11 Mai 2015
Your function currently has eighteen (18) outputs... and this is clearly difficult to keep track of. As an alternative you might like to consider using a structure, which allows you to do this:
function out = temp(x)
out.data = x;
out.sqrt = sqrt(x);
end
and then we can call the function and get all of the output values in just one variable:
>> X = temp(4)
X =
data: 4
sqrt: 2
This has many advantages over trying to pass lots of output variables! You can also use the same method for passing input variables :)
Julia
Julia am 11 Mai 2015
I see the advantage of using structures. The question is, why does my current output get overwritten?

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Stephen23
Stephen23 am 11 Mai 2015
Bearbeitet: Stephen23 am 11 Mai 2015
Solution
Those loops are very confused. Neither the while nor the for loop is being used effectively.
  • The for loop does absolutely nothing at all: you provide it with exactly one scalar value zMin, and so it "loops" over just one value... but there is no looping happening with just one value!
  • Using a while loop is not the best choice, as you already know precisely the start and end values for the loop. This is exactly what for loops are for.
Both of these could be replaced by one simple for loop:
zMin=30;
zMax=35;
for k = zMin:zMax
a(1,1,k) = k;
end
Bonus Extension
Or perhaps an even better solution (this depends on what you are doing with that matrix) is to not to use the values 30 to 35 directly as indices (and so fill up the rest of the matrix with useless zeros), but instead to use independent indices to locate the values:
zMin=30;
zMax=35;
vec = zMin:zMax;
for k = numel(vec):-1:1
a(1,1,k) = vec(k);
end
which we can view in the command window:
>> a
a(:,:,1) =
30
a(:,:,2) =
31
a(:,:,3) =
32
a(:,:,4) =
33
a(:,:,5) =
34
a(:,:,6) =
35
This is a much smaller matrix, and it contains only actual data, as opposed to the many useless zeros in your original matrix.
  5 Kommentare
Stephen23
Stephen23 am 11 Mai 2015
Bearbeitet: Stephen23 am 11 Mai 2015
Please upload your exact Mfile using the paperclip button, note that you have to click both the Choose file and Attach file buttons. I cannot read minds, and you will need to provide your exact code if you want a diagnosis of this problem.
That style of indexing should work fine:
function [out,F,E] = temp(n,x)
for k = n:-1:1
out(:,:,k) = x^k + [0,1;10,100];
[F(k),E(k)] = log2(out(1,1,k));
end
and tested:
>> [A,F,E] = temp(5,2)
A(:,:,1) =
2 3
12 102
A(:,:,2) =
4 5
14 104
A(:,:,3) =
8 9
18 108
A(:,:,4) =
16 17
26 116
A(:,:,5) =
32 33
42 132
F =
0.5 0.5 0.5 0.5 0.5
E =
2 3 4 5 6
Julia
Julia am 13 Mai 2015
Thank you.

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