Better way to keep dimensions using reshape from extracted struct array?
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Javier Cuadros
am 20 Aug. 2024
Kommentiert: Voss
am 20 Aug. 2024
HEllo
I am wondering what is the best way to extract the data from an structured array in matlab and keeping is dimensionality if I use reshape while processing it.
Let's say I have the following struct array
load('data.mat')
myData.data.b
In order to extract all b values I would do
[myData.data(:).b]
But this rises the issue that the dimensionality of b is lost, since now it is treated as an vector. If I do reshape to try to recover that dimensionality I will get
bb=reshape([myData.data(:).b]',[],2)
which is still not the original data, because all even row are swapped compared to original. So the only thing I came up was to undo that swapping on even rows via
bb(2:2:end,:) = fliplr(bb(2:2:end,:))
Hence I wonder whether there exists a better way to extract b from the struct array without having to do the reshape + even elemen flip.
thanks in advance,
Bes regards
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Stephen23
am 20 Aug. 2024
"I didn't know that I could use it in that way!"
You can use comma-separated lists with any function.
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arushi
am 20 Aug. 2024
Hi Javier,
To extract data from a structured array in MATLAB while preserving its original dimensionality, you can use a combination of array manipulation functions that maintain the structure of your data. In your case, since each element of myData.data(:).b is a 1x2 vector, you can use reshape and cell2mat in a way that respects the original organization of the data.
Here’s a more efficient approach to extract b values from the struct array without manually flipping rows:
- Extract Data into a Cell Array: Use arrayfun to extract the data into a cell array, preserving the structure.
- Convert to a Matrix: Use cell2mat to convert the cell array into a matrix.
bMatrix = cell2mat(bCellArray');
bOriginal = reshape(bMatrix, [], 2);
Hope this helps.
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