How to extract values from a matrix using a row - column matrix?

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VIJENDRA
VIJENDRA am 22 Apr. 2015
Kommentiert: VIJENDRA am 23 Apr. 2015
I have a matrix like
A =
0.2180 0.5714 0.2476 0.3942 0.9253 0.5082
0.3906 0.5881 0.6529 0.3806 0.3819 0.7947
0.3381 0.0287 0.0652 0.3696 0.3735 0.1351
0.7459 0.0911 0.0163 0.7531 0.3298 0.2050
0.3690 0.5010 0.5201 0.6119 0.9038 0.1902
0.4232 0.9183 0.6523 0.2392 0.4661 0.0019
and a matrix having row and column indices
loc =
1 2
2 5
4 3
6 6
I want the extract the values of locations (1,2), (2,5), (4,3) and (6,6) from matrix A when I do this
val = A(loc(:,1),loc(:,2));
it gives me
val =
0.5714 0.9253 0.2476 0.5082
0.5881 0.3819 0.6529 0.7947
0.0911 0.3298 0.0163 0.2050
0.9183 0.4661 0.6523 0.0019
I can use diag(val); to get the locations values but is there any way so that i could get values directly without getting that square matirx
val =
0.5714
0.3819
0.0163
0.0019

Akzeptierte Antwort

Stephen23
Stephen23 am 22 Apr. 2015
Bearbeitet: Stephen23 am 22 Apr. 2015
Yes! You can use sub2ind to achieve this:
A = [...
0.2180 0.5714 0.2476 0.3942 0.9253 0.5082
0.3906 0.5881 0.6529 0.3806 0.3819 0.7947
0.3381 0.0287 0.0652 0.3696 0.3735 0.1351
0.7459 0.0911 0.0163 0.7531 0.3298 0.2050
0.3690 0.5010 0.5201 0.6119 0.9038 0.1902
0.4232 0.9183 0.6523 0.2392 0.4661 0.0019];
loc = [...
1 2
2 5
4 3
6 6];
X = sub2ind(size(A), loc(:,1), loc(:,2));
and then run this in the command window:
>> A(X)
ans =
0.5714
0.3819
0.0163
0.0019

Weitere Antworten (1)

Punit
Punit am 22 Apr. 2015
[nRows nCols ] = size(A);
A(nRows*(loc(2)-1)+loc(1))
  1 Kommentar
Guillaume
Guillaume am 22 Apr. 2015
This is what sub2ind does and I'd recommend using it as it works regardless of the number of dimensions of A.

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