Image hidding using DWT
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Karbala'a Unvi. Science
am 15 Jun. 2024
Bearbeitet: Walter Roberson
am 19 Jun. 2024
Hello every one
I am finding a problime in my code for hidding 325*325 image into 2300*2300 image after decompose it using into HH{3} to get the best PSNR and MSE
and the erroe say that the matrix in not matching.
the code is as follow:-
% Main code
clc
close all;
clear all;
%
a=imgetfile();
coverImage1 = imread(a);
coverImages = imresize(coverImage1,[2600 2600]);
R=coverImages(:,:,1); %red = 1, green = 2, blue = 3
G=coverImages(:,:,2);
B=coverImages(:,:,3);
coverImage=B;
% figure;
% imshow(coverImage);
% title('Blue Image');
%%%%%
b=imgetfile();
secretImage1 = imread(b);
%secretImage=B1;
secretImage= rgb2gray(secretImage1);
secretImage = imresize(secretImage,[1300 1300]);
row = size(secretImage,1);
col = size(secretImage,2);
s = row*col;
%secretImage = imresize(secretImage,[280 280]);
% figure(1); imshow (coverImages)
% figure(2); imshow (secretImage)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Perform DNA encryption on the secret image
key = randi([0, 255], size(secretImage)); % Generate random key
encryptedImage = DNAEncrypt(secretImage, key);
%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
nColors = 256;
n =3 ; %# Number of decompositions
LL = cell(1,n); %# Approximation coefficient storage
LH = cell(1,n); %# Horizontal detail coefficient storage
HL = cell(1,n); %# Vertical detail coefficient storage
HH = cell(1,n); %# Diagonal detail coefficient storage
X = coverImage ;
for i = 1:n %# %# Apply nLevel decompositions
[LL{i},LH{i},HL{i},HH{i}] = dwt2(X,'Haar');
X = LL{i}; % gives you the last quarter of the image
end
%coverImage = LL{i}; % gives you the last quarter of the image
%alpha = 0.02; % Embedding strength
OO= HH{1}; OOO = HH{2}; OOOO=HH{3};% here I want to get the need HH{1,2,3} for the good hidding
%%
HH_embedded = HH{1} + ( encryptedImage);
stegoImage = idwt2(LL{i}, LH{i}, HL{i}, HH_embedded, 'haar');
imshow(uint8(stegoImage));
% %%
% tiledImage = wcodemat(LL{n},nColors);
% for i = n:-1:1
% tiledImage = cat(1,cat(2,tiledImage,...
% wcodemat(LH{i},nColors)),...
% cat(2,wcodemat(HL{i},nColors),...
% wcodemat(HH{i},nColors)));
% end
% figure(1);imshow(uint8(tiledImage-1));
%%
B2=uint8(stegoImage);
RGB= cat(3, R, G, B2);
stg= double(im2gray(RGB));
% figure (5)
% subplot(1, 2, 1);
% imshow(RGB);
% title('RGB after Analysis');
%%%%
% Display the stego image
figure;
subplot(1, 2, 1);
imshow(coverImages);
title('Cover Image');
subplot(1, 2, 2);
imshow(RGB);
title('Stego Image');
%%%%%%%%%%%%%
%TT = immse(stg, double(coverImage));
mse = sum(sum((coverImage - uint8(stg)) .^ 2)) / numel(coverImage);
% Display the MSE
fprintf('Mean Squared Error (MSE): %.4f\n', mse);
%CC = mse(stgcoverImage);
C = psnr((uint8(stg)),coverImage);
%fprintf('\n The Mean Sq. Erorr value is %0.4f', CC );
fprintf('\n PSNR value is %0.6f', C);
%%
%
I will write the code here and provide you the images, hope to get it down
2 Kommentare
Image Analyst
am 17 Jun. 2024
I'm not familiar with your algorithm. Does it expect the cover image and secret image to have the same dimensions? Which line throws the error?
By the way, there is a function for mse: immse
Akzeptierte Antwort
Umar
am 18 Jun. 2024
Bearbeitet: Walter Roberson
am 19 Jun. 2024
% Main code
clc
close all; clear all;
a = imgetfile(); coverImage1 = imread(a); coverImages = imresize(coverImage1, [2600 2600]); R = coverImages(:,:,1);
%red = 1, green = 2, blue = 3
G = coverImages(:,:,2); B = coverImages(:,:,3); coverImage = B;
b = imgetfile(); secretImage1 = imread(b); secretImage = rgb2gray(secretImage1); secretImage = imresize(secretImage, [1300 1300]); row = size(secretImage, 1); col = size(secretImage, 2); s = row * col;
key = randi([0, 255], size(secretImage));
% Generate random key
encryptedImage = DNAEncrypt(secretImage, key);
nColors = 256; n = 3; %# Number of decompositions
LL = cell(1, n); %# Approximation coefficient storage
LH = cell(1, n); %# Horizontal detail coefficient storage
HL = cell(1, n); %# Vertical detail coefficient storage
HH = cell(1, n); %# Diagonal detail coefficient storage
X = coverImage;
for i = 1:n %# Apply nLevel decompositions
[LL{i}, LH{i}, HL{i}, HH{i}] = dwt2(X, 'Haar'); X = LL{i};
% gives you the last quarter of the image
end
% Ensure the sizes of LL, LH, HL, and HH match the cover image
LL = cellfun(@(x) imresize(x, size(coverImage)), LL, 'UniformOutput', false); LH = cellfun(@(x) imresize(x, size(coverImage)), LH, 'UniformOutput', false); HL = cellfun(@(x) imresize(x, size(coverImage)), HL, 'UniformOutput', false); HH = cellfun(@(x) imresize(x, size(coverImage)), HH, 'UniformOutput', false);
HH_embedded = HH{1} + encryptedImage; stegoImage = idwt2(LL{i}, LH{i}, HL{i}, HH_embedded, 'haar'); imshow(uint8(stegoImage));
B2 = uint8(stegoImage); RGB = cat(3, R, G, B2); stg = double(im2gray(RGB));
figure; subplot(1, 2, 1); imshow(coverImages); title('Cover Image'); subplot(1, 2, 2); imshow(RGB); title('Stego Image');
mse = sum(sum((coverImage - uint8(stg)) .^ 2)) / numel(coverImage); fprintf('Mean Squared Error (MSE): %.4f\n', mse);
C = psnr(uint8(stg), coverImage); fprintf('\n PSNR value is %0.6f', C);
14 Kommentare
Umar
am 19 Jun. 2024
the reconstruction of the stego image needs to be corrected. The correct wavelet coefficients should be used to reconstruct the stego image accurately.
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