Stl file pdegplot in App designer
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    Jigar
 am 17 Mai 2024
  
    
    
    
    
    Bearbeitet: Cris LaPierre
    
      
 am 20 Mai 2024
            Hi, 
I am looking for a solution to find names of the faces after importing the stl file. pdegplot command does that but how can I use it in App Designer. I am trying the command but it throws different error. Looked for a solution but it isn't available. 
Is there any other command where i can use it to see name faces in the App designer so that i can use it to apply BC.
Thanks,
Jigar
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  Adam Danz
    
      
 am 17 Mai 2024
        
      Bearbeitet: Adam Danz
    
      
 am 17 Mai 2024
  
      > pdegplot command does that but how can I use it in App Designer?
pdegplot does not have an input argument or property to specify the parent axes.  This often poses a propblem in AppDesigner and uifigures in general since the default HandleVisible property in uifigures is 'off'.  This prevents pdegplot from finding the axes within the uifigure resulting in the generation of a new figure external to the app.  
I suppose this is the problem you're running into. 
This workaround describes how to temporarily make the app's axes accessible and current so that the pdegplot will add content to the existing axes.  
Here's a quick example.  See the previous link for details.  
% Mimick an app
app.UIFigure = uifigure(); 
app.UIAxes = uiaxes(app.UIFigure); 
% Change handle visibility
origState = app.UIFigure.HandleVisibility; 
handleVisCleanup = onCleanup(@()set(app.UIFigure,'HandleVisibility',origState));
app.UIFigure.HandleVisibility = 'on'; 
% Make axes current
set(groot, 'CurrentFigure', app.UIFigure)
set(app.UIFigure,'CurrentAxes',app.UIAxes)
% Plot pdegplot
g = [2	 1      1     1      1     1      1     1     1     4     4;
    -1	-0.6   -0.5  -0.4   -0.5   0.4	  0.5	0.6   0.5  -1	  0.17;
     1	-0.5   -0.4  -0.5   -0.6   0.5    0.6   0.5   0.4   0.17  1;
     0	-0.25  -0.35 -0.25  -0.15 -0.25  -0.35 -0.25 -0.15  0    -0.74;
     0	-0.35  -0.25 -0.15  -0.25 -0.35	 -0.25 -0.15 -0.25 -0.74  0;
     0	 0      0     0      0     0      0     0     0     1     1;
     1	 1      1     1      1     1      1     1     1     0     0;
     0  -0.5   -0.5  -0.5   -0.5   0.5    0.5   0.5   0.5   0     0;
     0  -0.25  -0.25 -0.25  -0.25 -0.25  -0.25 -0.25 -0.25  0     0;
     0	 0.1    0.1   0.1    0.1   0.1    0.1   0.1   0.1   1     1;
     0	 0      0     0      0     0      0     0     0     0.75  0.75;
     0	 0      0     0      0     0      0     0     0     0     0];
 pdegplot(g)
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