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Stl file pdegplot in App designer

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Jigar
Jigar am 17 Mai 2024
Bearbeitet: Cris LaPierre am 20 Mai 2024
Hi,
I am looking for a solution to find names of the faces after importing the stl file. pdegplot command does that but how can I use it in App Designer. I am trying the command but it throws different error. Looked for a solution but it isn't available.
Is there any other command where i can use it to see name faces in the App designer so that i can use it to apply BC.
Thanks,
Jigar
  1 Kommentar
Cris LaPierre
Cris LaPierre am 17 Mai 2024
What error are you getting? Please share all the red text.

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Adam Danz
Adam Danz am 17 Mai 2024
Bearbeitet: Adam Danz am 17 Mai 2024
> pdegplot command does that but how can I use it in App Designer?
pdegplot does not have an input argument or property to specify the parent axes. This often poses a propblem in AppDesigner and uifigures in general since the default HandleVisible property in uifigures is 'off'. This prevents pdegplot from finding the axes within the uifigure resulting in the generation of a new figure external to the app.
I suppose this is the problem you're running into.
This workaround describes how to temporarily make the app's axes accessible and current so that the pdegplot will add content to the existing axes.
Here's a quick example. See the previous link for details.
% Mimick an app
app.UIFigure = uifigure();
app.UIAxes = uiaxes(app.UIFigure);
% Change handle visibility
origState = app.UIFigure.HandleVisibility;
handleVisCleanup = onCleanup(@()set(app.UIFigure,'HandleVisibility',origState));
app.UIFigure.HandleVisibility = 'on';
% Make axes current
set(groot, 'CurrentFigure', app.UIFigure)
set(app.UIFigure,'CurrentAxes',app.UIAxes)
% Plot pdegplot
g = [2 1 1 1 1 1 1 1 1 4 4;
-1 -0.6 -0.5 -0.4 -0.5 0.4 0.5 0.6 0.5 -1 0.17;
1 -0.5 -0.4 -0.5 -0.6 0.5 0.6 0.5 0.4 0.17 1;
0 -0.25 -0.35 -0.25 -0.15 -0.25 -0.35 -0.25 -0.15 0 -0.74;
0 -0.35 -0.25 -0.15 -0.25 -0.35 -0.25 -0.15 -0.25 -0.74 0;
0 0 0 0 0 0 0 0 0 1 1;
1 1 1 1 1 1 1 1 1 0 0;
0 -0.5 -0.5 -0.5 -0.5 0.5 0.5 0.5 0.5 0 0;
0 -0.25 -0.25 -0.25 -0.25 -0.25 -0.25 -0.25 -0.25 0 0;
0 0.1 0.1 0.1 0.1 0.1 0.1 0.1 0.1 1 1;
0 0 0 0 0 0 0 0 0 0.75 0.75;
0 0 0 0 0 0 0 0 0 0 0];
pdegplot(g)
  10 Kommentare
Jigar
Jigar am 19 Mai 2024
Bearbeitet: Jigar am 19 Mai 2024
editing
I take my words back. It is working with an app property. Thanks for all the help!
Adam Danz
Adam Danz am 20 Mai 2024
Glad that it all worked out, thanks for the demo @Cris LaPierre!

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