Filter löschen
Filter löschen

Find data from txt file

7 Ansichten (letzte 30 Tage)
Cem Eren Aslan
Cem Eren Aslan am 29 Apr. 2024
Kommentiert: Voss am 29 Mai 2024
Hi all,
I try to find a data from txt file. In a row (i don't known which row), there is an information like "Dt: 0.0001". I want to find this row and store 0.0001 as a variable. How can i do that?
Thanks for help
  5 Kommentare
Cem Eren Aslan
Cem Eren Aslan am 30 Apr. 2024
There are two types of txt file. I attach both of them below:
First txt type:
PEER STRONG MOTION DATABASE RECORD. PROCESSING BY PACIFIC ENGINEERING.
IMPERIAL VALLEY 5/19/40 0439, EL CENTRO ARRAY #9, 180 (USGS STATION 117)
ACCELERATION TIME HISTORY. FILTER POINTS: HP=0.2 Hz LP=15.0 Hz
NPTS= 4000, DT= .01000 SEC
Acceleration (m/sec2)
-0.06281522
-0.05914169
0.00520338
0.07596138
0.06759460
....
Second txt type:
Earthquake: Imperial Valley 10/15/79
Station: El Centro Array #11
Component: 230
Dt: 0.005 sec
# of Data: 7807
Source: PEER Strong Motion Database
Site Class: Z3
Acceleration (m/sec2)
0.0267573
0.0294902
0.011642
-0.0165857
-0.0165209
-0.0169276
.....
Stephen23
Stephen23 am 30 Apr. 2024
@Cem Eren Aslan: please upload a sample data file by clicking the paperclip button.

Melden Sie sich an, um zu kommentieren.

Antworten (2)

Voss
Voss am 30 Apr. 2024
Bearbeitet: Voss am 30 Apr. 2024
filename = 'file1.txt';
dt = str2double(regexpi(fileread(filename),'dt. (.*) sec','tokens','once'))
dt = 0.0100
filename = 'file2.txt';
dt = str2double(regexpi(fileread(filename),'dt. (.*) sec','tokens','once'))
dt = 0.0050

Mathieu NOE
Mathieu NOE am 30 Apr. 2024
Simply using the suggested methods , you can access your DT data this way
I simply created two data files from you post
I used lower to convert all characters to lower case which then ease the process
% first file
out = fileread('data1.txt')
out =
'PEER STRONG MOTION DATABASE RECORD. PROCESSING BY PACIFIC ENGINEERING. IMPERIAL VALLEY 5/19/40 0439, EL CENTRO ARRAY #9, 180 (USGS STATION 117) ACCELERATION TIME HISTORY. FILTER POINTS: HP=0.2 Hz LP=15.0 Hz NPTS= 4000, DT= .01000 SEC Acceleration (m/sec2) -0.06281522 -0.05914169 0.00520338 0.07596138 0.06759460'
str = extractBetween(lower(out),'dt','sec');
A = regexp(str,'[-+]?([0-9]*[.])?[0-9]+([eE][-+]?\d+)?','match'); % extract numerical content of string
dt_value = str2double(A{1})
dt_value = 0.0100
% second file
out = fileread('data2.txt')
out =
'Earthquake: Imperial Valley 10/15/79 Station: El Centro Array #11 Component: 230 Dt: 0.005 sec # of Data: 7807 Source: PEER Strong Motion Database Site Class: Z3 Acceleration (m/sec2) 0.0267573 0.0294902 0.011642 -0.0165857 -0.0165209'
str = extractBetween(lower(out),'dt','sec');
A = regexp(str,'[-+]?([0-9]*[.])?[0-9]+([eE][-+]?\d+)?','match'); % extract numerical content of string
dt_value = str2double(A{1})
dt_value = 0.0050
  3 Kommentare
Cem Eren Aslan
Cem Eren Aslan am 29 Mai 2024
Yes but not this way. I solved the problem by using AI. Thank you
Voss
Voss am 29 Mai 2024
@Cem Eren Aslan: What solution did AI give you?

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Data Import and Analysis finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by