The min(y) function where y is a vector

If i have used a loop say

for x=1:1:10
    y(x)=(x^2)/2
end

then use min(y) to display the minimum from this vector, 0.5. How would I get it to display the corresponding x value?

thanks

Answer 1

[Fangjun Jiang]

In your code, x is a scalar. It is over-written every iteration in the for-loop.

min() can return the index.

x=1:10;
y=x.^2/2;
[ymin,pos]=min(y);
x_val=x(pos)

Answer 2

[Wayne King]

[minval,index] = min(y);

In this case it's trivial since index is the x value at which the minimum occurs. This function is increasing on your x values, so the minimum is at the first element.