Equivalent Impedance using Matrix, Eigen value and Eigen vector, norm
Ältere Kommentare anzeigen
I am solving this below problem(attachment 1). How to find the exp(theta1) and exp(theta2)...?
- Attachment pdf.pdf is the problem I am trying to solve.
- Attachment Tzeng_2006_J._Phys._A__Math._Gen._39_8579.pdf is the theory
Y11 =1-1i/sqrt(3); Y12 =1i/sqrt(3); Y13 =-1;
Y21 =1i/sqrt(3); Y22 =0; Y23 =-1i/sqrt(3);
Y31 =-1; Y32 =-1i/sqrt(3); Y33 =1+1i/sqrt(3);
Y11 = Y12 + Y13 ; Y22 = Y21 + Y23 ; Y33 = Y31 + Y32 ;
L = [Y11, Y12, Y13; Y21, Y22, Y23; Y31, Y32, Y33];
[EVector,EValue] = eig(L'*L) ; % V = Values % D = VECTORS
Sigma_2 = sqrt(EValue(2,2))
Sigma_3 = sqrt(EValue(3,3))


3 Kommentare
John D'Errico
am 8 Nov. 2023
You already know how to use eig. It returns all of the eigenvalues, and their associated eigenvectors.
Throw away all of the eigenvalues that are negative, as well as the eigenvectors associated with the ones you don't want. Toss any that are complex too, if that is a problem. What remains are the non-negative eigenvalues, as well as their eigenvectors.
So where is the problem?
RAJA KUMAR
am 9 Nov. 2023
Q = @(v) sym(v);
Y11 = 1-1i/sqrt(Q(3)); Y12 = 1i/sqrt(Q(3)); Y13 = Q(-1);
Y21 = 1i/sqrt(Q(3)); Y22 = Q(0); Y23 = -1i/sqrt(Q(3));
Y31 = -1; Y32 = -1i/sqrt(Q(3)); Y33 = 1+1i/sqrt(Q(3));
Y = [Y11, Y12, Y13; Y21, Y22, Y23; Y31, Y32, Y33; Y41, Y42, Y43]
A = L'*L ; % e = eig(L_P*L);
[V,EVC] = eig(A) % V = Values % D = VECTOR
Antworten (0)
Kategorien
Mehr zu Linear Algebra finden Sie in Hilfe-Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!