Can anyone explain from the third line till the end of below code..??

1 Ansicht (letzte 30 Tage)
Sombaran Gupta
Sombaran Gupta am 13 Apr. 2015
Bearbeitet: Thorsten am 14 Apr. 2015
a=imread('kmeans.jpg');
imshow(255-rgb2gray(a));
b=reshape(double(255-rgb2gray(a)),[],1);
[idx,c]=kmeans(b,2,'emptyaction','singleton');
Fin_a=reshape(idx,[size(rgb2gray(a))]);
[ind1, ind2]=find(Fin_a(:,:)==2);
[ind3, ind4]=find(Fin_a(:,:)==1);
figure();
imshow(255-rgb2gray(a));
hold on
if(length(ind1)<length(ind3))
scatter(ind2,ind1,'g');
else
scatter(ind4,ind3,'g');a
end
  1 Kommentar
Thorsten
Thorsten am 14 Apr. 2015
Bearbeitet: Thorsten am 14 Apr. 2015
Why don't you just run the code line by line and use doc and read what the functions are doing? And then ask again if you can't figure out particular parts/lines.

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Antworten (1)

Chris McComb
Chris McComb am 13 Apr. 2015
The third line from the end contains only the word 'else'. This is typical syntax for the if control structure. In the example, if length(ind1)<length(ind3), the program executes
scatter(ind2,ind1,'g');
However, if length(ind1)<length(ind3) is not true, the program will try to execute:
scatter(ind4,ind3,'g');a
and exit with an error, because the line ends with an 'a' character.
  2 Kommentare
John D'Errico
John D'Errico am 14 Apr. 2015
I think the question was asking for an explanation starting from line 3 until the end, not the third line from the end.
Sombaran Gupta
Sombaran Gupta am 14 Apr. 2015
yes from the third line till the end.

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