Can anyone explain from the third line till the end of below code..??

a=imread('kmeans.jpg');
imshow(255-rgb2gray(a));
b=reshape(double(255-rgb2gray(a)),[],1);
[idx,c]=kmeans(b,2,'emptyaction','singleton');
Fin_a=reshape(idx,[size(rgb2gray(a))]);
[ind1, ind2]=find(Fin_a(:,:)==2);
[ind3, ind4]=find(Fin_a(:,:)==1);
figure();
imshow(255-rgb2gray(a));
hold on
if(length(ind1)<length(ind3))
scatter(ind2,ind1,'g');
else
scatter(ind4,ind3,'g');a
end

1 Kommentar

Thorsten
Thorsten am 14 Apr. 2015
Bearbeitet: Thorsten am 14 Apr. 2015
Why don't you just run the code line by line and use doc and read what the functions are doing? And then ask again if you can't figure out particular parts/lines.

Melden Sie sich an, um zu kommentieren.

Antworten (1)

The third line from the end contains only the word 'else'. This is typical syntax for the if control structure. In the example, if length(ind1)<length(ind3), the program executes
scatter(ind2,ind1,'g');
However, if length(ind1)<length(ind3) is not true, the program will try to execute:
scatter(ind4,ind3,'g');a
and exit with an error, because the line ends with an 'a' character.

2 Kommentare

I think the question was asking for an explanation starting from line 3 until the end, not the third line from the end.
yes from the third line till the end.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Creating, Deleting, and Querying Graphics Objects finden Sie in Hilfe-Center und File Exchange

Tags

Gefragt:

am 13 Apr. 2015

Bearbeitet:

am 14 Apr. 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by