Overall intensity calculation from an image

Hi,
I want to calculate the overall intensity of this image here. I have separated this red channel from an RGB flurescence image. Please guide me on how to do this.

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Image Analyst
Image Analyst am 22 Sep. 2023

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Not sure what you mean by overall intensity. You can get the red channel like this
redChannel = rgbImage(:, :, 1);
% Get sum of all pixel values:
sumOfValues = sum(redChannel(:))
% Get mean value of image intensity over all image pixels
meanIntensity = mean2(redChannel)

6 Kommentare

Mahe Jabeen
Mahe Jabeen am 22 Sep. 2023
I am doing something like this. But your approach is much easier. I am not sure why I am getting different values than yours. I converted it to gray image. Maybe it is not necessary to convert to gray image to get the sum of the intensity. Let me know what you think.
unprocessed_image=imread("G:\My Drive\codes\STB CT 30 rep1 100 pM_ hCG SDC1_ 1_c2x0-1024y0-1024.tif");
Grey_image=rgb2gray(unprocessed_image);
imshow(Grey_image);
meanIntensityValue = mean(mean(Grey_image));
[pixelCounts, grayLevels] = imhist(Grey_image);
sum_pixel=sum(pixelCounts (:,1));
DGM
DGM am 22 Sep. 2023
Bearbeitet: DGM am 22 Sep. 2023
rgb2gray() calculates luma. If all image content is in the red channel alone, then it's merely scaled by 0.299, so that's probably why you're seeing a difference. I don't see why it would be appropriate to do that, since we're not concerned with how the human eye responds to varied hues in the same image. Just extract the red channel by itself.
Mahe Jabeen
Mahe Jabeen am 23 Sep. 2023
@DGM Thanks for the feedback. Yes, I agree.
Image Analyst
Image Analyst am 23 Sep. 2023
Summing the pixel counts from the histogram will merely count the number of pixels in the image so if you have a million pixels in your image, the sum of the histogram counts will be a million pixels. It will not give you the sum of all pixel values like I did. But again, we don't know your formula for "overall intensity" -- that's a very vague description that could be taken different ways.
Mahe Jabeen
Mahe Jabeen am 23 Sep. 2023
Hi @Image Analyst, yes I agree with your point. My values were switched in the code I pasted and was calculating sum of intensity of all the gray pixels, not the sum of pixels.
Image Analyst
Image Analyst am 23 Sep. 2023
If this Answer solves your original question, then could you please click the "Accept this answer" link to award the answerer with "reputation points" for their efforts in helping you? They'd appreciate it. Thanks in advance. 🙂 Note: you can only accept one answer (so pick the best one) but you can click the "Vote" icon for as many Answers as you want. Voting for an answer will also award reputation points.

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