Split increasing vector into n unqueal parts based on multiples of n
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Konvictus177
am 18 Sep. 2023
Beantwortet: Stephen23
am 18 Sep. 2023
Hi,
I have a vector which consists of increasing numbers.
I want to split the vector into 54 parts based on multiples of 2030. So first vector should contain all numbers from 0 until 2030. Second vector should contain all numbers from 2030 and up until 2*2030 (4060), third vector everything from 4060 up until 3*2030 (6090), etc.
Vector is attached.
Thanks.
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Dyuman Joshi
am 18 Sep. 2023
load('Denc.mat')
m=max(Denc)
m/2030
You want to ignore the 55th, 56th and the 57th parts?
Also, just to confirm, you want to include the boundary values on both sides?
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Stephen23
am 18 Sep. 2023
S = load('Denc.mat');
D = S.Denc
B = 0:2300:2300+max(D)
X = discretize(D,B);
C = accumarray(X,D,[],@(a){a})
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