creat stateflow use script

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wenchao zhang
wenchao zhang am 14 Aug. 2023
Kommentiert: wenchao zhang am 14 Aug. 2023
hello,when i run the following script,error happens, any one knows what the root reason, following are the script.
sfnew
rt = sfroot;
ch = find(rt,'-isa','Stateflow.Chart');
st = Stateflow.State(ch);
view(st)
j1 = Stateflow.Junction(ch);
j1.Position.Radius = 16.18;
j1.Position.Center = [31.41 27.18];
j2 = Stateflow.Junction(ch);
j2.Position.Radius = 16.18;
j2.Position.Center = [62.41 27.18];
transition = Stateflow.Transition(ch);
transition.Source = j1;
transition.Destination = j2;
transition.LabelString = '{xx;yy;zz;}';
  2 Kommentare
Fangjun Jiang
Fangjun Jiang am 14 Aug. 2023
No error in R2022b. What is the error message?
wenchao zhang
wenchao zhang am 14 Aug. 2023
ok,thanks,may be it is caused by lost the state flow license, tomorrow i will check again. may be some command not supported in 2019a, not sure

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