Record block isn't producing a "recordout" field
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I am recording a sine wave and a ramp in simulink using the record block. When I go into the workspace and type "out" into the cmd line, the only field available to me is "tout". How do I make sure that the record block has a "recordout" field? Because when I open the record's block parameters, it just takes me to some graphs
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1455912/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1455917/image.png)
1 Kommentar
Walter Roberson
am 13 Aug. 2023
In the diagram you show, the model does not do anything except have a couple of input signals and a record block. What sample rate did you configure, and what simulation stop time did you configure? And did you configure discrete or continuous simulation?
Antworten (1)
Fangjun Jiang
am 14 Aug. 2023
"out" is a Simulink.SimulationOutput object. By default, it records the root level outputs. You don't have any Outport blocks.
The simulation has been run. out.tout shows that.
Repeat your step above and then double click the Record block, check "Record to Workspace" button and re-run the simulation, then you will see out.recordout
0 Kommentare
Siehe auch
Kategorien
Mehr zu Simulink Coder finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!