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Adam
Adam am 10 Aug. 2023

1 Stimme

It's a sparse array so that is standard.
You can use:
full( kio )
to convert to a full (standard) matrix if you wish, though be aware that it will take more memory. Obviously for a 78x78 matrix this is not an issue though.

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John D'Errico
John D'Errico am 10 Aug. 2023
Adam is completely correct of course. I would only add the additional point that a sparse 78x78 matrix is REALLY small these days. Any computations will not be that much faster for such a small matrix. Sparse matrix computations might even be slower. It is worth testing for your matrix.

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Michael
Michael am 10 Aug. 2023

0 Stimmen

Your matrix "val" is a sparse matrix. You can convert it to a full storage matrix with the function "full".
A = full(val)

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Joe
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