How to control the house temperature using a fan system?
Ältere Kommentare anzeigen
I am modeling a fan system that is able to reduce the temperature of the house when it exceeds a certain set temperature.
The idea is to use the difference between the set temperature and the house temperature to tune and control whether the fan system comes on to cool down the house temperature in case it's too high and vice versa. It should be able to control and maintain a certain temperature in the house.
This is where I am stuck, I don't know how to control the house temperature to a desired set temperature using the fan system.
Attached is the simulink file.
All the help is appreciated thanks.
3 Kommentare
John D'Errico
am 17 Jul. 2023
Why would a fan be able to control the teperature of a house? Sorry, but your goal is a bit strange.
Consider a case where the outside temperature is 35 degrees C, and the internal temperature is 30 degrees C.
Now using only a fan, tell us what mechanism you would use to reduce the internal temperature of the house below the current 30 degrees C.
Similarly, suppose the outside temp is 10 degrees. Explain how you would use a fan to increase the internal house temperature above that point.
Until you explain what mechanism you would use (one that does not contradict the laws of thermodynamics) you cannot perform this task.
hunter manana
am 17 Jul. 2023
If the indoor temperature is decreasing naturally, it's because heat is being lost to the outdoors. Ventilation only accelerates the process. It's not clear to me where you're storing heat otherwise, but then again, I can't open the .slx file. Latest version of simulink I have installed is R2015b.
Antworten (1)
I'm unsure of how your house temperature control mechanism works. But if based on the thermal dynamics provided, then this is probably how the math produces magic (see User-defined parameters section). I also do not know how your PID works. Perhaps you can translate the given math into something that your PID control block recognizes.

tspan = linspace(0, 1, 10001);
T0 = 30; % Initial house temperature
[t, T] = ode45(@odefcn, tspan, T0);
% Solution Plot
plot(60*t, T, 'linewidth', 1.5),
ylim([18 32]), grid on,
xlabel('Time / min'), ylabel('Temperature / °C')
yline(23, '--', '23°C', 'LabelVerticalAlignment', 'Bottom')
% Ordinary Differential Equation function
function Tdot = odefcn(t, T) % (T = Thouse)
% Thermal Resistance of the House
Req = 0.0000004; % C/J-hr
% Mass of air present in the house
M = 5987.7684; % kg
% Specific heat capacity of air
c = 1005.4; % J/kg-C
% Outside temperature (assumed to be measurable)
Tout = 23 + 5*sin(2*pi/24*t);
% User-defined parameters (set the values as indicated, the rest are 'laws')
ts = 20/60; % desired settling time (hr) <-- set this one
k = 5/ts; % thermal control rate <-- maybe related to the heater's capacity
Tref = 23; % reference temperature <-- and this one
Tgain = (- Req*M*c*k*(T - Tref) + T - Tout)/Req;
% Thermal dynamics
Tloss = (T - Tout)/Req;
Tdot = (Tgain - Tloss)/(M*c);
end
Kategorien
Mehr zu General Applications finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
