How do I extract a structure array from a single dynamic structure without using for loops?

5 Ansichten (letzte 30 Tage)
Im trying to derive a structure array from a single structure without using for loops.
1) I make n copies of the original structure, primal
primalSP = repmat(primal,n,1)
2) I have n sets of m states in the struct primal.states. The size of primal.states is (n*m, nodes) . I want the first set of m states to go to the first structure array, and the second set to the second structure array and so on until all n sets are assigned, like this
primalSP(1).states = primal.states(1:n,:);
primalSP(2).states = primal.states(n+1:2*n,:);
...
Is there a way to do this without a for loop where n is dynamic?
  3 Kommentare
Shelley Snider
Shelley Snider am 5 Jun. 2023
I'm failiar with those functions. I'm having a hard time understandng how to put them together to get what I want.
Stephen23
Stephen23 am 5 Jun. 2023
"I want the first set of m states to go to the first structure array, and the second set to the second structure array and so on until all n sets are assigned"
Then your example should be:
primalSP(1).states = primal.states(1:m,:);
primalSP(2).states = primal.states(m+1:2*m,:);

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Matt J
Matt J am 6 Jun. 2023
Bearbeitet: Matt J am 6 Jun. 2023
There is no way to avoid for-loop speed when dealing with structs and cells. Below is a way to abbreviate the syntax, but both num2cell.m and mat2cell.m have for-loops within them, as you will see if you read those files.
stateCell = num2cell(primal.states,1);
[primalSP(1:n).states] = deal(stateCell{:});

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Produkte


Version

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by