Can you place ui-components in uigridlayout using Name-Value pair input?
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uif = uifigure;
uig = uigridlayout('Parent', uif, ...
'ColumnWidth', repmat({'1x'}, 1, 5), ...
'RowHeight', repmat({'1x'}, 1, 3));
uib = uibutton('Parent', uig, ...
'Text', 'I want to be placed in one line')
% Put this lines inside 'uibutton' initialisation:
uib.Layout.Column = 3;
uib.Layout.Row = 2;
I searched for something able to create an instance of GridLayoutOptions, but i can't find anything.
An alternative would be to understand how matlab.ui.layout.LayoutOptions would accept inputs.
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`GridLayoutOptions` is a specific subclass of `LayoutOptions` that applies to grid layouts, so you can create an instance of `GridLayoutOptions` as follows:
% Create a grid layout and a button
uif = uifigure;
uig = uigridlayout(uif);
uib = uibutton(uig, 'Text', 'I want to be placed in one line');
% Create and set GridLayoutOptions properties
glo = matlab.ui.layout.GridLayoutOptions;
% Set row span width
glo.RowSpan = [1 1]; % default
% Set column span width
glo.ColumnSpan = [1 5];
% Assign GridLayoutOptions object to button
uib.Layout.Row = 2;
uib.Layout.Column = 1;
uib.Layout.GridLayoutOptions = glo;
Here, `glo` is a `GridLayoutOptions` object that specifies the row span and column span of the button, and is assigned to the `GridLayoutOptions` property of the button's layout. You could modify the `RowSpan` and `ColumnSpan` properties of `glo` to suit your layout needs.
Alternatively, you could use the `LayoutOptions` object directly without creating a `GridLayoutOptions` object, as follows:
uib.Layout.Row = 2;
uib.Layout.Column = 1;
uib.Layout.RowSpan = [1 1];
uib.Layout.ColumnSpan = [1 5];
Here, the `RowSpan` and `ColumnSpan` properties of `LayoutOptions` are set directly.
Refer to the following resources
I hope this helps you customize the layout options of your app! Let me know if you have any further questions.
1 Kommentar
chicken vector
am 16 Jun. 2023
Eden Winga
am 3 Mai 2024
0 Stimmen
This is a similar question, but I'm trying to create a 2048 game in the GUI app designer, but I can't seem to figure out how to access a GridLayout component by its handle or name. I have label components in a 4x4 gridlayout and want to change the text in the label from 0 to 2 or 4 randomly. How would i make a for loop that goes through every element in the 4x4 grid and randomly generate a 2 or 4?
1 Kommentar
Les Beckham
am 28 Jun. 2024
Perhaps this will get you started (adapted from David's answer above). Although this doesn't use app designer.
uif = uifigure;
uig = uigridlayout('Parent', uif, ...
'ColumnWidth', repmat({'1x'}, 1, 4), ...
'RowHeight', repmat({'1x'}, 1, 4));
values = randi(2,1,16) * 2;
for i = 1:numel(values)
[row, col] = ind2sub([4 4], i);
uib = uilabel('Parent', uig, ...
'Text', num2str(values(i)), 'Layout', ...
matlab.ui.layout.GridLayoutOptions('Row', row, 'Column' , col), ...
'HorizontalAlignment', 'center');
end
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