Removing rows except containing certain numbers of "33"

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Smithy am 26 Mai 2023
Kommentiert: Stephen23 am 1 Jun. 2023
Hello everybody,
I hope to keep the row with the containing certain numbers of "33" of the last two digits in 1st column of result.
and I hope to remove other rows.
the expecting answer is [133 1133; 2, 4] in this case. ()
I tried with
result(~ismember(result(:,1),'33'), :) = []; % It does not work.
result(~contains(string(result(:,1)),"33"), :) = []; % 332 also is included in result variable.
but it doest not work. 332 also is included in result variable.
Is there a way to check wheter last two digits meet the condition?
x = [103 133 1133 1344 332 105 1105 15 53 511]';
y = [1 2 4 5 7 2 1 8 10 1]';
result = [x,y];
% How to remove the rows except containing certain numbers of 1st column of result
% if I would like to keep the row with the "33" of the last two digits in 1st column of result,
% 133 and 1133 accept the condition. and 332 does not meet the condition.
% so the expecting result will be [133 2; 1133, 4]
result(~ismember(result(:,1),'33'), :) = []; % It does not work.
result(~contains(string(result(:,1)),"33"), :) = []; % 332 also is included in result variable.
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Stephen23 am 26 Mai 2023
As Dyuman Joshi correctly wrote, mixing up text and numeric data will not help you.
Just stick to the numeric domain and use MOD or REM.

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Akzeptierte Antwort

Hiro Yoshino am 26 Mai 2023
You should use "pattern" to detect what you want in the strings as follows:
x = [103 133 1133 1344 332 105 1105 15 53 511]';
y = [1 2 4 5 7 2 1 8 10 1]';
result = [x,y]
result = 10×2
103 1 133 2 1133 4 1344 5 332 7 105 2 1105 1 15 8 53 10 511 1
Define pattern
pat = "33";
TF = endsWith(string(result(:,1)),pat);
Extract what I want
result(TF,:)
ans = 2×2
133 2 1133 4
Does this fit what you want to achieve?
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Smithy am 26 Mai 2023
Thank you very much for your huge helps. I really really appreciate with it. It works really well for me.

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Weitere Antworten (1)

Dyuman Joshi am 26 Mai 2023
You are trying to compare numeric data with character data. You will have to convert your initial data to do that comparison.
Instead, just use rem() or mod()
x = [103 133 1133 1344 332 105 1105 15 53 511]';
y = [1 2 4 5 7 2 1 8 10 1]';
%Checking condition - last two digits correspond to 33
idx = rem(x,100)==33;
%Values corresponding to the condition
result = [x(idx)';y(idx)']
result = 2×2
133 1133 2 4
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Stephen23 am 1 Jun. 2023
+1 simpler and more efficient without the superfluous type conversions.

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