Please what did i do wrong here..using interp2
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i was given a table of y\x and the given values of the corresponding temperatures, and i was told to find the estimate of the temperature at (1.2,0.7). i did my code but it did not seem to be right when i ran it .here is the code:
y=0.0:0.5:2.0;
x=0.0:0.5:2.5;
T= [0.00 5.00 10.00 15.00 20.00;
5.00 7.51 10.00 12.51 15.00;
10.00 10.05 10.00 9.95 10.00;
15.00 12.70 10.00 7.32 5.00;
20.00 15.67 10.00 4.33 0.00;
25.00 20.00 10.00 0.00 -5.00;];
Tn= interp2(x,y,T,1.2,0.7)
Antworten (2)
Image Analyst
am 11 Apr. 2015
All too common of a beginners mistake. You thought x,y = row,column. It's NOT. In other words, you swapped x and y. Remember the rows = y, not x like you had them, and the columns = x, not y like you had. So x,y = columns, rows, NOT rows, columns. Here is corrected code:
x=0.0:0.5:2.0;
y=0.0:0.5:2.5;
T= [0.00 5.00 10.00 15.00 20.00;
5.00 7.51 10.00 12.51 15.00;
10.00 10.05 10.00 9.95 10.00;
15.00 12.70 10.00 7.32 5.00;
20.00 15.67 10.00 4.33 0.00;
25.00 20.00 10.00 0.00 -5.00;];
whos y
whos x
size(T)
Tn= interp2(x,y,T,1.2,0.7)
5 Kommentare
ggeneral
am 11 Apr. 2015
Image Analyst
am 11 Apr. 2015
No it doesn't. x is columns, y is rows. Look again. Also, your T is wrong - doesn't match your textbook. It seems to be transposed or something.
ggeneral
am 11 Apr. 2015
ggeneral
am 11 Apr. 2015
Image Analyst
am 11 Apr. 2015
They show a 5 row by 6 column table. You have a 6 row by 5 column table. And, no, semicolons are not required when writing out a table on multiple lines.
Star Strider
am 11 Apr. 2015
@George — As I read Problem 2, you transposed the table. It’s supposed to be (5x6). Yours is (6x5). Transpose ‘T’ (use the (') transpose operator to avoid retyping it) and your code should work.
y=0.0:0.5:2.0;
x=0.0:0.5:2.5;
T= [0.00 5.00 10.00 15.00 20.00;
5.00 7.51 10.00 12.51 15.00;
10.00 10.05 10.00 9.95 10.00;
15.00 12.70 10.00 7.32 5.00;
20.00 15.67 10.00 4.33 0.00;
25.00 20.00 10.00 0.00 -5.00;];
T = T';
Tn= interp2(x,y,T,1.2,0.7)
produces:
Tn =
10.6660
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