How can we increase/decrease the number of triangles in a triangulation that is created from a polyshape object?

I wrote the following code:
C1 = polyshape(X1,Y1);
C2 = polyshape(X2,Y2);
C = subtract(C1,C2);
T = triangulate(C);
where X1, X2, Y1 & Y2 are column vectors of x- & y-coordinates of points that define the outer and inner boundaries of a region. The last command breaks the region C into triangles. My question is: How can we increase or decrease the numbr of triangles in the triangualtion or is it fixed?

Antworten (3)

To increase the number of triangles, you would have to add vertices along the edges, like in the following:
p1= polyshape([0,0; 1 0; 0 1]);
p2=polyshape([0,0,; 1 0; 0.5,0.5,;0,1],'Simplify',0);
doPlot(p1)
doPlot(p2)
function doPlot(p)
figure
plot(p,'FaceColor','g'); hold on
triplot(triangulation(p),'r'); hold off
axis equal
end

4 Kommentare

Thank you Matt for your answer. Actually I already tried increasing the vertices but it didn't work. The polyshape function automatically deleted vertices that lie on a straight line except the two extreme ones. But I'm using ver2018. Maybe in the latest version this may not be the case.
I don't think it's any different in 2018. You need to set 'Simplify'='off' like in my posted code.
Add a very tiny bit of noise to the coordinates so they're no longer on a perfectly straight line.
Thank you Matt & Image Analyst for your valuable inputs. Yes, when I use 'Simplify',0) in the polyshape command it starts working. So I get the two figures shown below. The traingles span the whole width of the hexagonal ring. Any idea how to have smaller triangles?

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To decrease the number of vertex points that describe a polygon while still somewhat resembling the original shape, see the algorithm in the attached paper.
Another way:
p1=nsidedpoly(6);
p2=p1.scale(0.5);
P=subtract(p1,p2);
P=subTri(P);
for i=1:3
P=splitTri(P);
end
plot(P); axis equal
function p=subTri(P)
%Sub-divide a scalar polyshape P into a vector of triangular sub-polyshapes
T=triangulation(P);
V=T.Points;
for i=height(T):-1:1
p(i)=polyshape(V(T(i,:),:));
end
p=p(:)';
end
function pnew=splitTri(p)
%Given a vector of triangular polyshapes, p, split each p(i) into smaller
%triangular polyshapes.
if isscalar(p)
V=interp1( p.Vertices([1,2,3,1],:) , 1:0.5:3.5);
pnew=subTri(polyshape(V,'Simplify',0));
else
C=arrayfun(@splitTri,p,'uni',0);
pnew=[C{:}];
end
end

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Gefragt:

am 20 Mai 2023

Bearbeitet:

am 22 Mai 2023

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