want to know the bytes of upperLeft image
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executing the code below
close all;
clear all;
imData=imread('lena256.bmp');
imshow(imData);
figure(1);
title('Original image');
pause(2);
map=gray(256);
[Lo_D,Hi_D,Lo_R,Hi_R] = wfilters('haar');
[N, M]=size(imData);
dwt_row_image=zeros(N, M);
tmpData=zeros(1, M);
for i=1:N
tmpData(1, 1:M)=imData(i, 1:M);
tmpData(1, 1:M)=dwt(tmpData, Lo_R);
dwt_row_image(i, 1:M)=tmpData(1, 1:M);
end
tmpData=zeros(1, N);
dwt1_imData=zeros(N, M);
for i=1:M
tmpData(1, 1:N)=dwt_row_image(1:N, i)';
tmpData(1, 1:N)=dwt(tmpData, Lo_R);
dwt1_imData(1:N, i)=tmpData(1, 1:N)';
end
figure(2);
imshow(dwt1_imData, map); % our first aim % shifting the image to the
title(' After DWT');
pause(2);
[rows, columns, numberOfColorChannels] = size(dwt1_imData);% edited by me
r1 = int32(M/2);
c1 = int32(N/2);
r2 = r1+1;
c2 = c1+1;
upperLeft = dwt1_imData(1:r1, 1:c1);
figure(3);
imshow(upperLeft, map);
dpcm22(upperLeft);
%------------function dpcm22--------------
function dpcm22(A)
[Height,Width,Depth] = size(A);
if Depth > 1
A1 = double(A(:,:,1));
else
A1 = double(A);
end
%
Qtype = 'uniform'; % ’uniform’ and ’nonuniform’
B = 5; % # bits of quantization
%hello();
*fileInfo = dir('upperLeft');*
[rows, columns, numberOfColorChannels] = size(A);
disp(fileInfo.bytes);
fileSizeInProgram = rows * columns * numberOfColorChannels
fprintf('File size on disk = %f bytes.\n', fileInfo.bytes);
fprintf('File size in program = %f bytes.\n', fileSizeInProgram);
comp_ratio=fileInfo.bytes / fileSizeInProgram;
disp(comp_ratio);
Now the problem is that the bold part is not working, please suggest how to get the bytes of upperLeft image as dir command is not working
3 Kommentare
Antworten (2)
Thomas Koelen
am 8 Apr. 2015
Bearbeitet: Thomas Koelen
am 8 Apr. 2015
a=whos('upperleft');
a.bytes
will give you the size of the variable
2 Kommentare
Image Analyst
am 8 Apr. 2015
I thought we talked about this before. Use dir() or imfinfo() to get the size on disk.
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