need help for take data from loop

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christiano doni
christiano doni am 6 Apr. 2015
Kommentiert: christiano doni am 6 Apr. 2015
I have scrip data like this
clear all;close all;clc
c1=imread('1200TIM-20150401-0010_20150401-1054015001500-1','png');
a1=double(c1);
a1=reshape(a1,2229000,[]);
c2=imread('1200TIM-20150401-0020_20150401-1054015001500-1','png');
a2=double(c2);
a2=reshape(a2,2229000,[]);
c3=imread('1200TIM-20150401-0030_20150401-1054015001500-1','png');
a3=double(c3);
a3=reshape(a3,2229000,[]);
and I have matrix
a1=(2229000,3); a2=(2229000,3); a3=(2229000,3);
and i want to make 3 matrix data like this
red=[a1(:,1),a2(:,1),a3(:,1)]
green=[a1(:,2),a2(:,2),a3(:,2)]
blue=[a1(:,3),a2(:,3),a3(:,3)]
*my questions is how to make loop for red, grean and blue because data a1, a2 until a100, i try *
for i=1:1:3; red(:,i)=['a'num2str(i)(:,1)]; end
but its not working here

Akzeptierte Antwort

Philipp Maier
Philipp Maier am 6 Apr. 2015
Bearbeitet: Philipp Maier am 6 Apr. 2015
The eval function can be used to execute the MATLAB expression. For example:
for i=1:1:3;
red(:,i)= eval(['a' num2str(i) '(:,1)'])';
end
Since I do not have the PNG-files that you are reading , I tested the code with three random variables:
a1 = rand(2229000,3);
a2 = rand(2229000,3);
a3 = rand(2229000,3);

Weitere Antworten (1)

Jan
Jan am 6 Apr. 2015
No, do not do this. It might work in this specific case, but it is in general an evil method and it produces more troubles than it solves. The problem is discussed several times a day and therefore you find it in the frequently asked questions also: http://www.mathworks.com/matlabcentral/answers/57445-faq-how-can-i-create-variables-a1-a2-a10-in-a-loop .
  1 Kommentar
christiano doni
christiano doni am 6 Apr. 2015
ok sir, move to you link.. thanks for you advice

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