Unique concatenation of multi-dimensional cell arrays

3 Ansichten (letzte 30 Tage)
Milos
Milos am 7 Mär. 2023
Kommentiert: Stephen23 am 8 Mär. 2023
I have 15, k x k x k cell arrays, stacked ontop of each other ,where each cell contians a row vector. I would like to concactenate each row vector living in the living the the same poisition cell for all 15 cell arrays such that each of the row vectors doesn't have any repetitions
For the sake of clarity, suppose we have only two cell arrays of size 3 x 3,
A(:,:,1) = {[1;2;3],[],[3];
[],[],[4];
[],[2;3],[]}
A(:,:,2) = {[2;3;4],[4],[3];
[],[],[4];
[],[2;4],[]}
%I'd like the output to be
C = {[1;2;3;4],[4],[3];
[],[],[4];
[],[2;3;4],[]}
%This is possible to do with a for loop where each step of the for loop
%looks like
C{i} = unique(cat(1,A{i},B{i}))
However, since k can be fairly large and vectors in each cell are very large this turns out to be very inefficent for me. I don't suppose anyone knows of a quick way to do this? Many Thanks.
Edit the uniqueness is no longer an issue since if say we are able to perform the concactenation to obtain;
D = {[1;2;3;1;2;3;4],[4],[3;3];
[],[],[4;4];
[],[2;2;3;4;4],[]}
C = cellfun(@(x)unique(x), D, 'UniformOutput', false);
What still remains unsolvable to me is how one could obtain D from A. I should add that I have tried
cat(1,A(:,:,1),A(:,:,2))
cat(2,A(:,:,1),A(:,:,2))
cat(3,A(:,:,1),A(:,:,2))
none of which yeild the desired result.

Akzeptierte Antwort

Matt J
Matt J am 7 Mär. 2023
A(:,:,1) = {[1;2;3],[],[3];
[],[],[4];
[],[2;3],[]};
A(:,:,2) = {[2;3;4],[4],[3];
[],[],[4];
[],[2;4],[]};
C = cellfun(@union,A(:,:,1),A(:,:,2),'UniformOutput',false)
C = 3×3 cell array
{4×1 double} {[ 4]} {[ 3]} {0×1 double} {0×1 double} {[ 4]} {0×1 double} {3×1 double} {0×1 double}
  1 Kommentar
Milos
Milos am 8 Mär. 2023
Ahh great this is even simpler! I'll accept this as the awnser now since it is simpler for me.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Voss
Voss am 7 Mär. 2023
A(:,:,1) = {[1;2;3],[],[3];
[],[],[4];
[],[2;3],[]};
A(:,:,2) = {[2;3;4],[4],[3];
[],[],[4];
[],[2;4],[]};
C = cellfun(@(a,b)unique([a;b]),A(:,:,1),A(:,:,2),'UniformOutput',false)
C = 3×3 cell array
{4×1 double} {[ 4]} {[ 3]} {0×1 double} {0×1 double} {[ 4]} {0×1 double} {3×1 double} {0×1 double}
  2 Kommentare
Milos
Milos am 8 Mär. 2023
ohhh I didn't know you could do this. I'm quite new to matlab and I'm a bit confused as to how the @(a,b)unique([a;b]) part works in cellfun. Do you have anysuggestions as to where I could read more about this?
Stephen23
Stephen23 am 8 Mär. 2023
"Do you have anysuggestions as to where I could read more about this?"

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by